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sergij07 [2.7K]
4 years ago
14

Show the proper sequence of synthetic transformations in the conversion of benzene to ethyl m-fluorophenyl ketone.

Chemistry
1 answer:
jeka944 years ago
8 0

Answer:

Then proper sequence is attached.

Explanation:

Show the proper sequence of synthetic transformations in the conversion of benzene to ethyl m-fluorophenyl ketone. Please give descriptions of each step and the reasoning behind it.

The proper sequence of synthetic transformations in the conversion of benzene to ethyl m-fluorophenyl ketone is attached.

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Plss answer the question in the picture. If you actually answer I will give you brainilest!!!
DedPeter [7]

Answer:

hey :)

your answer is D.

Explanation:

To find density, you must divide mass and volume.

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4 divided by 2 is 2

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6 0
3 years ago
Consider the equation: 2NO2(g) N2O4(g). Using ONLY the information given by the equation which of the following changes would in
Reika [66]
I believe the correct answer is the first option. To increase the molar concentration of the product N2O4, you should increase the pressure of the system. You cannot determine the effect of changing the temperature since we cannot tell whether it is an endothermic or an exothermic reaction. Also, decreasing the number of NO2 would not increase the product rather it would shift the equilibrium to the left forming more reactants. The only parameter we can change would be the pressure. And, since NO2 takes up more space than the product increasing the pressure would allow the reactant to collide more forming the product.
7 0
3 years ago
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What is the [H+] if the pH is 13.6?
MrRa [10]

Answer:

8???

Explanation:

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8 0
3 years ago
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I don't quite understand it
irina1246 [14]
So, you need to have same ammount of atoms on the left and on the right side of the equation. You need to count the ammount of attoms of every substance on the left, and make sure that on the right side the ammount is same. For example in the 1st one it’s 6Sn+2P4=2Sn3P4, so that you have 6atoms of Sn on the left and 6 atoms of Sn on the right, same with the P
6 0
3 years ago
What is the volume in liters of 321 g of liquid with a density of 0.84 g/mL
Rasek [7]
Density is weight by volume.   

First.  If you divide the weight by density you can find the volume

Second you must convert the ML in to Liters.

\frac{321 \frac{g}{1}}{0.84 \frac{g}{mL}} = \frac{321(g)(mL)}{0.84g}=\frac{321mL}{0.84}=382.14mL

1L=1000ml

\frac{1L}{1000mL}

(382.14mL)( \frac{1L}{1000mL})= \frac{(382.14mL)(L)}{1000mL} =\frac{382.14L}{1000}=0.38214L

0.38214 Liters.

4 0
4 years ago
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