Answer:
{5π/6, 11π/6}
Step-by-step explanation:
Since you have memorized the trig values of common angles, you know tan(π/6) = 1/√3, so cot(π/6) = √3.
The solution to this equation is ...
cot(θ) = -√3
so θ = -π/6 or, in the domain of interest, 11π/6. There is a corresponding quadrant II angle, 5π/6.
Answer:
First image attached
The error was done in Step E, because student did not multiply
by the negative sign in numerator. Step E must be
.
Second image attached
The error was done in Step C, because the student omitted the
of the algebraic identity
. Step C must be 
Step-by-step explanation:
First image attached
The error was done in Step E, because student did not multiply
by the negative sign in numerator. The real numerator in Step E should be:

Hence, Step E must be
.
Second image attached
The error was done in Step C, because the student omitted the
of the algebraic identity
. Step C must be 
And further steps are described below:
Step D

Which according to the Quadratic Formula, represents a polynomial with complex roots. That is: (
,
,
)


(Conjugated complex roots)
Step E

Step F

The answers is 3/9 which you can check by reducing. It reduces to 1/3. Basically you go 1/3 = x/9 then cross multiple to get 9=3x do the division so 3x/3 and 9/3 and you get 3/9.
B. Y=4x-14
Think about where the point is on the grid and then use the slope to get to the y-intercept. So for this question your going to have to move backwards to get to the y axis. Move down 12 units and left 3 and that’ll give you the y-intercept which will match in the equation.