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egoroff_w [7]
3 years ago
9

The equation of line AB is y = 5x + 1. Write an equation of a line parallel to line AB in slope-intercept form that contains poi

nt (4, 5).
y = 5x − 15

y = 5x + 15

y = 1 over 5x + 21 over 5

y = 1 over 5x − 29 over 5
Mathematics
2 answers:
Andreas93 [3]3 years ago
8 0
Y = 5x + 1...the slope here is 5...a parallel line will have the same slope.

y = mx + b
slope(m) = 5
(4,5)...x = 4 and y = 5
now we sub and solve for b, the y int
5 = 5(4) + b
5 = 20 + b
5 - 20 = b
-15 = b
so ur parallel equation is : y = 5x - 15

dezoksy [38]3 years ago
5 0
The equation of the line y = 5x + 1. Line that is parallel to the function given should have the same slope as the equation which is 5. We use the point-slope form in order to find the second equation that contains the point (4,5).

y - 5 = 5(x-4)
y = 5x - 20 + 5
y = 5x -15

Therefore, the correct answer is the first option.
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In triangle JKL, if angle J is seven less than angle L and angle K is 21 less than twice angle L, find the measure of each angle
saul85 [17]

Answer:

L = 52°

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Step-by-step explanation:

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K = 2L - 21

J + K + L = 180°

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4L - 28 = 180

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L = 52°

J = 52 - 7 = 45°

K = 2 x 52 - 21 = 83°

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Viefleur [7K]

Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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3 years ago
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Answer:

Step-by-step explanation:

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3 years ago
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