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gayaneshka [121]
3 years ago
11

when magnesium is burned in air the mass of the product is greater than the mass of the solid magnesium burned. A student claims

that this is a violation of the Low of conservation of mass do you agree or disagree with the claim. justify your answer
Chemistry
2 answers:
Nikitich [7]3 years ago
5 0
Veg egverbygbe rbbnfghjufddfg
il63 [147K]3 years ago
4 0
No, this is not a violation of the Law of conservation because when Magnesium is burnt it reacts with oxygen to form magnesium oxide. This end product is going to weigh more than the solid magnesium due to the addition of oxygen.
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The wavelength of a wave can be found by measuring how high the wave is measuring how many waves pass a point in a second measur
Liono4ka [1.6K]

Now that you know something about the properties of the two main types of waves (Lesson 43), we need to make sure that you can look at individual characteristics that waves can have.

<span>Not all waves are created equal!<span>You need to be able to see the specific “faces” that each wave can have, based on three important characteristics: frequency, wavelength, and amplitude.</span></span>Frequency

When we first started looking at SHM we defined period as the amount of time it takes for one cycle to complete... seconds per cycle

<span><span>Frequency is the same sort of idea, except we’re just going to flip things around.</span><span>Frequency is a measurement of how many cycles can happen in a certain amount of time… cycles per second.</span><span>If a motor is running so that it completes 50 revolutions in one second, I would say that it has a frequency of 50 Hertz.</span><span>Hertz is the unit of frequency, and just means how many cycles per second.<span><span>It is abbreviated as Hz.</span><span>It is named after Heinrich Hertz, one member of the Hertz family that made many important contributions to physics.</span></span></span><span>In formulas frequency appears as an "f".</span></span>

Since frequency and period are exact inverses of each other, there is a very basic pair of formulas you can use to calculate one if you know the other…

It is very easy to do these calculations on calculators using the x-1 button.

Example 1: The period of a pendulum is 4.5s. Determine the frequency of this pendulum.

<span>The period means that it will take 4.5 seconds for the pendulum to swing back and forth once. So, I expect that my frequency will be a decimal, since it will complete a fraction of a swing per second.</span>Wavelength

Wavelength is a property of a wave that most people (once they know what to look for) can spot quickly and easily, and use it as a way of telling waves apart. Look at the following diagram...

Figure 1<span><span>Any of the parts of the wave that are pointing up like mountains are called crests. Any part that is sloping down like a valley is a trough.</span><span>Wavelength is defined as the distance from a particular height on the wave to the next spot on the wave where it is at the same height and going in the same direction.Usually it is measured in metres, just like any length.</span><span>There isn’t a special spot you have to start on a wave to measure wavelength, just make sure you are back to the same height going in the same direction. Most people do like to measure from one crest to the next crest (or trough to trough), just because they are easy to spot.</span></span>Figure 2

On a longitudinal wave, the wavelength is measured as the distance between the middles of two compressions, or the middles of two expansions.

Figure 3

This leads us to one of the most important formulas you will use when studying waves.

<span><span>Frequency tells us how many waves are passing a point per second, the inverse of time.</span><span>Wavelength tells us the length of those waves in metres, almost like a displacement.</span><span>If we multiply these two together, we are really multiplying 1/s and m… which gives us m/s, the velocity of the wave!</span></span>

v = velocity of the wave (m/s)
f = frequency (Hz)
λ = wavelength (m)

Example 2: A wave is measured to have a frequency of 60Hz. If its wavelength is 24cm, determine how fast it is moving.

Example 3: The speed of light is always 3.00e8 m/s. Determine the frequency of red light which has a wavelength of 700nm.

Be careful when changing the 700nm into metres. Some people get really caught up with changing it into regular scientific notation with only one digit before the decimal. Why bother? It's only being used in a calculation. You’ll probably just make a mistake changing the power of 10, so just substitute in the power for the prefix and leave everything else alone…700 nm = 700 x 10-9 m since “nano” is 10-9.

Amplitude

Amplitude is a measure of how big the wave is.

<span>Imagine a wave in the ocean. It could be a little ripple or a giant tsunami.<span>What you are actually seeing are waves with different amplitudes.<span>They might have the exact same frequency and wavelength, but the amplitudes of the waves can be very different.</span></span></span>

The amplitude of a wave is measured as:

<span><span>the height from the equilibrium point to the highest point of a crest or</span><span>the depth from the equilibrium point to the lowest point of a trough</span></span>Figure 4

When you measure the amplitude of a wave, you are really looking at the energy of the wave.

<span>It takes more energy to make a bigger amplitude wave.<span>Anytime you need to remember this, just think of a home stereo’s amplifier… it makes the amplitude of the waves bigger by using more electrical energy.</span></span>
6 0
3 years ago
The combustion of 135 mg of a hydrocarbon produces 440 mg of CO2 and 135 mg H2O. The molar mass of the hydrocarbon is 270 g/mol.
NeX [460]

Answer:

Molecular formula = C20H30

Explanation:

NB 440mg = 0.44g, 135mg= 0.135g

From the question, moles of CO2= 0.44/44= 0.01mol

Since 1 mol of CO2 contains 1mol of C, it implies mol of C = 0.01

Also from the question, moles of H2O = 0.135/18= 0.0075mole

Since 1 mol of H2O contains 2mol of H, it implies mol of H = 0.0075×2= 0.015 mol of H

To get the empirical formula, divide by smallest number of mole

Mol of C = 0.01/0.01=1

Mol of H = 0.015/0.01= 1.5

Multiply both by 2 to obtain a whole number

Mol of C =1×2 = 2

Mol of H= 1.5×2 = 3

Empirical formula= C2H3

[C2H3] not = 270

[ (2×12) + 3]n = 270

27n = 270

n=10

Molecular formula= [C2H3]10= C20H30

5 0
3 years ago
Which is the most accurate description of compounds?
Alex787 [66]
The answer has to be D
8 0
3 years ago
Read 2 more answers
To what family of the periodic table does this new element probably belong
julsineya [31]
<span>Ionization energy (IE) is the amount of energy required to remove an electron. If you observe the IEs sequentially, there is a large gap between the 2nd and 3rd. This suggests it is difficult to remove more than 2 two electrons. Elements that lose two electrons to become more stable are found in the Group 2A (2 representing the number of electrons in the outermost valence shell).</span>
6 0
3 years ago
A 3.3 g sample of sodium hydrogen carbonate is added to a solution of acetic acid weighing 10.3 g. The two substances react, rel
Zanzabum

Answer:

1.73g of CO2.

Explanation:

We'll begin by writing the balanced equation for the reaction. This is given below:

NaHCO3 + CH3COOH → CH3COONa + H2O + CO2

Next we shall determine the masses of NaHCO3 and CH3COOH that reacted and the mass of CO2 produced from the balanced equation. This is illustrated below:

Molar mass of NaHCO3 = 23 + 1 + 12 + (16x3) = 84g/mol

Mass of NaHCO3 from the balanced equation = 1 x 84 = 84g

Molar mass of CH3COOH = 12 + (3x1) + 12 + 16 + 16 + 1 = 60g/mol

Mass of CH3COOH from the balanced equation = 1 x 60 = 60g

Molar mass of CO3 = 12 + (2x16) = 44g/mol

Mass of CO2 from the balanced equation = 1 x 44 = 44g

From the balanced equation above,

84g of NaHCO3 reacted with 60g of CH3COOH to produce 44g of CO2.

Next, we shall determine the limiting reactant of the reaction. This is illustrated below:

From the balanced equation above,

84g of NaHCO3 reacted with 60g of CH3COOH.

Therefore, 3.3g of NaHCO3 will react with = (3.3 x 60)/84 = 2.36g of CH3COOH.

From the above illustration, we can see that only 2.36g of CH3COOH out of 10.3g given reacted completely with 3.3g of NaHCO3. Therefore, NaHCO3 is the limiting reactant while CH3COOH is the excess reactant.

Finally, can determine the mass of CO2 produced during the reaction.

In this case the limiting reactant will be used because it will produce the mass yield of CO2 as all of it were used up in the reaction. The limiting reactant is NaHCO3 and the mass of CO2 produced is obtained as shown below:

From the balanced equation above,

84g of NaHCO3 reacted to produce 44g of CO2.

Therefore, 3.3g of NaHCO3 will react to produce = (3.3 x 44)/84 = 1.73g of CO2.

Therefore, 1.73g of CO2 is released during the reaction.

7 0
3 years ago
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