Answer:
<em>(B.) What is the molar solubility of barium chloride, BaCl2 in water? </em>
Explanation:
Molar solubility is the number of moles of a substance that can dissolve in a liter of solution to the point of the solution's saturation. It can be calculated stoichiometrically from a substance's solubility product constant in mol/L.
Since all the 
reacted all the 
from the information, we can easily assume all the substances were consumed in the reaction, and hence account for their purity. Furthermore, 
is insoluble in water, the most probable scientific query would be the molar solubility of the used in the experiment.
Answer:
minimum number of trays:
N = 7 trays
Explanation:
minimum number (N):
- N = ( Log ( (Xd / ( 1 - Xd )) * (( 1 - Xb ) / Xb )) ) / Log α....Fenske's Eq. binary mixture
∴ α = 2.5
∴ Xd = 0.96.......molar fraction the distillate
∴ Xb = 0.04 .........molar fraction in the bottoms
⇒ N = ( Log ( ( 0.96 / ( 1 - 0.96 ) ) * ( ( 1 - 0.04 ) / 0.04 )) ) / Log ( 2.5 )
⇒ N = 6.94 ≅ 7 trays
First, take the molar mass of B (10.81g) and divide the value you've been given by the molar mass to get moles (5.4 / 10.81). So you have .5 moles of B and then you need to convert that to atoms. To do that you must use the constant 6.022X10^23 atoms per mole. Take your moles and multiply it by that constant. Your final answer should be (3.01X10^23) atoms.
Hope this helps!
Answer:
38.75 L
Explanation:
From the question,
Applying Boyles Law,
PV = P'V'....................... Equation 1
Where P = Original pressure of the Argon gas, V = Original Volume of Argon gas, P' = Final pressure of Argon gas, V' = Final Volume of Argon gas.
make V the subject of the equation
V = P'V'/P.................... Equation 2
Given: P = 34.6 atm, V' = 456 L, P' = 2.94 atm.
Substitute these values into equation 2
V = (456×2.94)/34.6
V = 38.75 L
