let "a number" = x
a number is divided by 3 => x/3
14 is added to the quotient => (x/3) + 14
The result is 33 => " = 33"
Solve for x
(x/3) + 14 = 33
Isolate the x. Note the equal sign. What you do to one side you do the other.
Subtract 14 from both sides
(x/3) + 14 (-14) = 33 (-14)
x/3 = 19
Isolate the x. Multiply 3 to both sides
x/3(3) = 19(3)
x = 19(3)
x = 57
57 is your original number
hope this helps
Answer:
C = 31
Step-by-step explanation:
Solve for c by simplifying both sides of the equation, then isolating the variable.
Answer:
The ordered pair is a solution to the equation
Step-by-step explanation:
Plug the ordered pair into the equation as (x,y):
y = -x + 8
4 = -4 + 8
4 = 4
Since both sides are equal to each other, then the ordered pair is a solution to the equation.
The addition property of equality justifies this. You could also say that she simply subtracted 7, and then it would be the subtraction property of equality. This is the case because if you add or subtract (or multiply or divide) the same number on both sides of an equation, the equation will still be the same.
Hope it helps!
of sand?