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r-ruslan [8.4K]
3 years ago
10

A gas occupies a volume of 34.5 L at 87.5 kPa and 23.5 C. The container can expand to the volume of 45.5 L. If conditions change

to 59.7 kPa and 33.6 C will the container be able to contain the resulting gas volume?
Chemistry
1 answer:
Sergio [31]3 years ago
4 0
The answer is no because if you use the combined gas law the volume would come out to be 52.3 liters.
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How many individual atoms are represented in the reactants of the equation shown below?
Soloha48 [4]

Answer:

There are 8 hydrogen atoms on the product side in the reaction.

Explanation:

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3 years ago
How many moles of water were lost if the amount of water lost was 0.456 grams? Do not include units and assume three significant
nika2105 [10]
<h3>Answer:</h3>

0.0253 mol H₂O

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table

<u>Stoichiometry</u>

  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[Given] 0.456 g H₂O (water)

<u>Step 2: Identify Conversions</u>

[PT] Molar Mass of H - 1.01 g/mol

[PT] Molar Mass of O - 16.00 g/mol

Molar Mass of H₂O - 2(1.01) + 16.00 = 18.02 g/mol

<u>Step 3: Convert</u>

  1. [DA] Set up:                                                                                                     \displaystyle 0.456 \ g \ H_2O(\frac{1 \ mol \ H_2O}{18.02 \ g \ H_2O})
  2. [DA] Multiply/Divide [Cancel out units]:                                                          \displaystyle 0.025305 \ mol \ H_2O

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

0.025305 mol H₂O ≈ 0.0253 mol H₂O

3 0
3 years ago
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BartSMP [9]

Answer:

<u><em></em></u>

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Explanation:

Charle's Law for ideal gases states that, at constant pressure, the <em>temperature</em> and the <em>volume</em> of a sample of gas are protortional.

                       \dfrac{V}{T}=k\\\\V=kT

That means that the graph of the relationship between Temperature, in Kelivn, and Volume is a line, which passes through the origin.

When you work with Temperature in Celsius, and the temperature is placed on the x-axis, the line is shifted to the left  273.15ºC.

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You cannot reach such low temperatures in an experiment, and also, volume zero is not real.

Nevertheless, you can draw the line of best fit and extend it until the x-axis (corresponding to a theoretical volume equal to zero), and read the corresponding temperature.

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2) deuterium (₁²H), with mass number 2 (one neutrons, n° = 2 -1, n° = 1).

3) tritium (₁³H), with mass number 3 (two neutrons, n° = 3 -1, n° = 2).

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Answer:

Living things in the ocean are able to move carbon from the atmosphere into surface waters.

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