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r-ruslan [8.4K]
3 years ago
10

A gas occupies a volume of 34.5 L at 87.5 kPa and 23.5 C. The container can expand to the volume of 45.5 L. If conditions change

to 59.7 kPa and 33.6 C will the container be able to contain the resulting gas volume?
Chemistry
1 answer:
Sergio [31]3 years ago
4 0
The answer is no because if you use the combined gas law the volume would come out to be 52.3 liters.
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If a 60-g object has a volume of 30 cm3, what is its density? 2 g/cm3 0.5 cm3/g 1800 g * cm3 none of the above
jasenka [17]

Answer : The density of an object is, 2g/cm^3

Solution : Given,

Mass of an object = 60 g

Volume of an object = 30cm^3

Formula used :

\text{Density of an object}=\frac{\text{Mass of an object}}{\text{Volume of an object}}

Now put all the given values in this formula, we get the density of an object.

\text{Density of an object}=\frac{60g}{30cm^3}=2g/cm^3

Therefore, the density of an object is, 2g/cm^3

6 0
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10: Convert 77.0 L at 18.0 mmHg to its new volume at standard pressure.
olchik [2.2K]

Answer:

The answer to your question is   V2 = 1.82 l

Explanation:

Data

Volume 1 = 77 l

Pressure 1 = 18 mmHg

Volume 2 = ?

Pressure 2 = 760 mmHg

Process

Use Boyle's law to solve this problem

                P1V1 = P2V2

-Solve for V2

                 V2 = P1V1/P2

-Substitution

                 V2 = (18 x 77) / 760

-Simplification

                 V2 = 1386 / 760

-Result

                 V2 = 1.82 l

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Answer:

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