A gas occupies a volume of 34.5 L at 87.5 kPa and 23.5 C. The container can expand to the volume of 45.5 L. If conditions change
1 answer:
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Answer:- C. Hafnium.
Solution:- Mass of the sample is 46.0 g and it's volume is .
From mass and volume, we can calculate it's density using the formula:
On the basis of the density, this substance could either be mercury or hafnium. Since the substance is a solid at room temperature where as mercury is liquid. So, it can't be mercury.
The right choice is C) Hafnium.