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r-ruslan [8.4K]
3 years ago
10

A gas occupies a volume of 34.5 L at 87.5 kPa and 23.5 C. The container can expand to the volume of 45.5 L. If conditions change

to 59.7 kPa and 33.6 C will the container be able to contain the resulting gas volume?
Chemistry
1 answer:
Sergio [31]3 years ago
4 0
The answer is no because if you use the combined gas law the volume would come out to be 52.3 liters.
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Chemical reactions H2SO4 +NaHCO3=​
Solnce55 [7]

Answer:

2NaHCO3 + H2SO4 -----> Na2SO4 + 2H2O + 2CO2.

Explanation:

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3 years ago
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An aqueous solution of 10.03 g of catalase, an enzyme found in the liver, has a volume of 1.05 L at 27°C. The solution's osmotic
-Dominant- [34]

Answer : The molar mass of catalase is, 2.40\times 10^5g/mol

Explanation :

Formula used :

\pi =CRT\\\\\pi=\frac{w}{M\times V}RT

where,

\pi = osmotic pressure  = 0.745 torr = 0.000980 atm   (1 atm = 760 torr)

C = concentration

R = solution constant  = 0.0821 L.atm/mol.K

T = temperature  = 27^oC=273+27=300K

w = mass of catalase = 10.03 g

M = molar mass of catalase = ?

V = volume of solution  = 1.05 L

Now put all the given values in the above formula, we get:

0.000980atm=\frac{10.03g}{M\times 1.05L}\times (0.0821L.atm/mole.K)\times (300K)

M=2.40\times 10^5g/mol

Therefore, the molar mass of catalase is, 2.40\times 10^5g/mol

7 0
3 years ago
Calculate the number of moles of solute in 27.55 mL of 0.1185 M K2Cr2O7(aq).
Zinaida [17]

Answer:

0.01185M = moles/0.02755L

0.02755*0.01185=0.00032647

Explanation:

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3 years ago
Which statement would support a merit of the Bronsted-Lowry base theory has over the Arrhenius base theory?
butalik [34]

Answer:

Explanation:

Bronsted Base is an H+ acceptor

No good answer Bronstead base does not accept hydroxide or electrons

5 0
3 years ago
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About 55L of a gas in a flexible container is under a pressure of 3.2 atm and at a temperature of 520K. What is the new volume o
vampirchik [111]

Answer:

30.62 L

Explanation:

From the question given above, the following data were obtained:

Initial volume (V₁) = 55 L

Initial pressure (P₁) = 3.2 atm

Initial temperature (T₁) = 520 K

Final temperature (T₂) = 760 K

Final pressure (P₂) = 8.4 atm

Final volume (V₂) =?

The final volume of the gas can be obtained as follow:

P₁V₁ / T₁ = P₂V₂ / T₂

3.2 × 55 / 520 = 8.4 × V₂ / 760

176 / 520 = 8.4 × V₂ / 760

Cross multiply

520 × 8.4 × V₂ = 176 × 760

4368 × V₂ = 133760

Divide both side by 4368

V₂ = 133760 / 4368

V₂ = 30.62 L

Therefore, the new volume of the gas is 30.62 L

7 0
3 years ago
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