Answer:
0.238 M
Explanation:
A 17.00 mL sample of the dilute solution was found to contain 0.220 M ClO₃⁻(aq). The concentration is an intensive property, so the concentration in the 52.00 mL is also 0.220 M ClO₃⁻(aq). We can find the initial concentration of ClO₃⁻ using the dilution rule.
C₁.V₁ = C₂.V₂
C₁ × 24.00 mL = 0.220 M × 52.00 mL
C₁ = 0.477 M
The concentration of Pb(ClO₃)₂ is:
Answer:
Do you want an explaniton to? btw the answer is
1 in the 13
2 in the 8
3 in the 42
4 in the Mo
5 in the 96
6 in the 1
7 in the 18
8 in the 2
Data:
Q (Amount of heat) = 832 J
m (mass) = ?
c (Specific heat) = <span>0.90 J/(g × ° C)
T (final) = 97 ºC
To (initial) = 20 ºC
</span>ΔT = T - To → ΔT = 97 - 20 → ΔT = 77 ºC
Formula:
Q = m*c*ΔT
Solving:
Q = m*c*ΔT
832 = m*0.90*77
832 = 69.3m
69.3m = 832
Answer:
Following are the complete balance of the given equation:
Explanation:
Given equation:
After Balancing the equation:
In the above equation, when the 3 mol Copper sulfate reacts with 2 mol lithium phosphate
, it will produce 2 mol Copper phosphate and 3 mol Lithium sulfate
.
