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joja [24]
3 years ago
7

PLEASE HELP ME ASAPPPPP How many moles are in 10.25 grams of NH3?

Chemistry
1 answer:
stich3 [128]3 years ago
8 0
10.25g NH3*( \frac{1mol NH3}{17.04g NH3} )=0.6015

0.6015 = 6.015*10^{-1} mol NH3

6.015*10^{-1} mol NH3 is the answer.
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Give the full electron configuration for nitrogen.
garri49 [273]

Answer:

1s2 2s2 2p3

Explanation:

3 0
2 years ago
Chandra wants to know how many moles are contained in 150.0 g ccl4 (carbon tetrachloride). what quantity of ccl4 should she use
Fynjy0 [20]

The quantity of carbon tetrachloride, CCl₄ she will use to make her conversion is molar mass

<h3>Description of mole </h3>

The mole of a substance is related to it's mass and molar mass according to the following equation:

Mole = mass / molar mass

<h3>How to determine the mole of CCl₄</h3>
  • Mass of CCl₄ = 30 g
  • Molar mass of CCl₄ = 12 + (35.5×4) = 154 g/mol
  • Mole of CCl₄ =?

Mole = mass / molar mass

Mole of CCl₄ = 150 / 154

Mole of CCl₄ = 0.974 mole

Thus, we can see that the molar mass of CCl₄ is needed to obtain the number of mole.

Learn more about mole:

brainly.com/question/13314627

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8 0
2 years ago
PLEASE HELP ME!!!! ILL FIND A WAY TO GET YOU 100 POINTS!!!
Umnica [9.8K]

It’s c had this problem last week

8 0
3 years ago
All the molecules of a substance possess the "average kinetic energy" value.
MaRussiya [10]

Answer:

true

Explanation:

when molecules of a solid substance is vibrating so, it means they are possessing average kinetic energy. thus, we can conclude that the statement all the molecules of a substance posses the average kinetic energy value is true.

3 0
3 years ago
14. In the lab, an experimenter mixes 75.0 g of water (initially at 30oC) with 83.8 g of a solid metal (initially at 600oC). At
avanturin [10]

Answer:

Tungsten is used for this experiment

Explanation:

This is a Thermal - equilibrium situation. we can use the equation.

Loss of Heat of the Metal = Gain of Heat by the Water

                      -Q_{m}=+Q_{w}\\

                    Q = mΔTC_{p}

Q = heat

m = mass

ΔT = T₂ - T₁

T₂ = final temperature

T₁ = Initial temperature

Cp = Specific heat capacity

<u>Metal</u>

m = 83.8 g

T₂ = 50⁰C

T₁ = 600⁰C

Cp = x

<u>Water</u>

m = 75 g

T₂ = 50⁰C

T₁ = 30⁰C

Cp = 4.184 j.g⁻¹.⁰c⁻¹

               -Q_{m}=+Q_{w}\\

⇒ - 83.8 x x x (50 - 600) = 75 x 4.184 x (50 - 30)

⇒ x = \frac{6276}{46090} = 0.13 j.g⁻¹.⁰c⁻¹

We know specific heat capacity of Tungsten = 0.134 j.g⁻¹.⁰c⁻¹

So metal Tungsten used in this experiment

8 0
3 years ago
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