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gavmur [86]
3 years ago
10

It is 762 miles from here to Chicago. An obese physics teacher jogs at a rate of 5.0 miles every 20.0 minutes. How long would it

take him to jog to Chicago if he jogged continuously and REALLY wanted to get there?
Chemistry
1 answer:
Lina20 [59]3 years ago
5 0

Answer:

3,048 minutes

Explanation:

762 divided by 5

that number times 20

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What type of air mass is Georgia most influenced by?
andriy [413]
It is most influenced by maritime tropical
7 0
3 years ago
What quantities are conserved when balancing a chemical reaction?
EleoNora [17]
The mass in a chemical reaction remains (mostly) the same.

(except for radiation/nuclear fission, in which mass gets converted into energy)
8 0
3 years ago
Observe the samples of quartz and garnet shown here. How do the minerals differ from one another? How are they alike?
Viefleur [7K]

Answer:

Garnet is a hard transparent mineral that is often used as gemstones and abrasives and quartz is the most abundant mineral on the earth's surface. They are both minerals that come out of the earth and that's about the most they have in common.

Explanation:

I got this answer correct.

6 0
2 years ago
A student caries out an experiment and dissolves 10.0 g of sodium bromide. NaBr, in 200g of water. What is the molality of the s
Pavel [41]

Answer:

0.485mol/kg

Explanation:

Molality is defined as the ratio of the number of moles of a solute to the kilogram of a solvent which is usually water.

Mass of NaBr = 10g

Molar mass of NaBr= 23+80=103g/mol

Mole of NaBr = mass / molar mass=10g/103g/mol= 0.097mol

Molality= Mole of a solute/ mass of solvent in kg

Mole of a solute( NaBr)= 0.097mol; mass of solvent( water in kg)= 200g. To convert to kg: 200g/1000g= 0.2kg

Molality = 0.097mol/0.2kg = 0.485mol/kg

4 0
3 years ago
What would be the volume in liters of an 2.45 liter sample of gas at 594 °C
Ber [7]

Answer:

V_2= 1.19L

Explanation:

Hello there!

In this case, since the STP conditions are defined by 1 atm (101.3 kPa) and 273 K, it is possible for us to use the combined gas law for this problem as we are given variable pressure, temperature and volume:

\frac{P_1V_1}{T_1} =\frac{P_2V_2}{T_2}

In such a way, solving for V2 as the final volume, we obtain:

V_2=\frac{P_1V_1T_2}{P_2T_1} =\frac{156kPa*2.45L*273.15K}{101.3kPa*(594+273)K}\\\\V_2= 1.19L

Regards!

6 0
3 years ago
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