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pochemuha
3 years ago
5

What three things are carried throughout the body by the cardiovascular system

Physics
1 answer:
Natasha_Volkova [10]3 years ago
8 0
Blood, vitamins, and cells :)

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yuradex [85]
I think unbalanced forces is one of the reasons
3 0
3 years ago
Lester plays middle linebacker for dices football team. During one play, he made the following movements. First, he back-pedaled
NikAS [45]

Answer:

Explanation:

missing info .....

4 0
2 years ago
a mass m at the end of a spring oscillates with a frequency of 0.78 hz . when an additional 730 g mass is added to m, the freque
ozzi

The value of mass m = 0.506kg

Initial frequency = 0.78Hz

additional mass =  730 g = 0.73kg

New frequency = 0.65 Hz

F = 1/2π \sqrt{x\\}k/m

0.78 =  1/2π \sqrt{k/m}

additional mass,

0.65 = 1/2π \sqrt{k/m+0.65}

1.44 = k/m / k/m+0.73

1.44 = m+0.73 / m

1.44m -m = 0.73

1.44m = 0.73

mass m = 0.506kg

a measurement used in physics to express the inertia, a quality that all matter has in common. Effectively, it is the resistance a body of matter offers to a change in its speed or position as a result of the application of a force. The change caused by an applied force is proportional to the mass of the body. The kilograms is the measure of mass in the International System of Units (SI). Its definition is based on the Planck constant, which is set at 6.62607015 1034 joule second. The unit of energy known as a joule is one kilogramme times one square metre per second. The kilogramme is determined by precise measurements of Planck's constant, while the second and metre are already defined in terms of other physical constants.

Learn more about mass here:

brainly.com/question/506625

#SPJ4

4 0
2 years ago
Using Hooke's law, F spring=k delta x, find the distance a spring with an elastic constant of 4 N/cm will stretch if a 2 newton
pishuonlain [190]

Hello!

Using Hooke's law, F spring=k delta x, find the distance a spring with an elastic constant of 4 N/cm will stretch if a 2 newton force is applied to it.

Data:

Hooke represented mathematically his theory with the equation:

F = K * Δx  

On what:

F (elastic force) = 2 N

K (elastic constant) = 4 N/cm

Δx (deformation or elongation of the elastic medium or distance from a spring) = ?

Solving:


F = K * \Delta{x}

2\:N = 4\:N/cm*\Delta{x}

4\:N/cm*\Delta{x} = 2\:N

\Delta{x} = \dfrac{2\:\diagup\!\!\!\!\!N}{4\:\diagup\!\!\!\!\!N/cm}

simplify by 2

\Delta{x} = \dfrac{2}{4}\frac{\div2}{\div2}

\boxed{\boxed{\Delta{x} = \dfrac{1}{2}\:cm}}\Longleftarrow(distance)\end{array}}\qquad\checkmark

Answer:

B.) 1/2 cm

_______________________

I Hope this helps, greetings ... Dexteright02! =)

7 0
3 years ago
If heat Q is required to increase the temperature of a metal object from 4 ∘C to 7∘C, the amount of heat necessary to increase i
alisha [4.7K]

Answer:

4Q

Explanation:

Case 1 :

m = mass of the metal

c = specific heat of the metal

\Delta T = Change in temperature = 7 - 4 = 3 C

Amount of heat required for the above change of temperature is given as

Q = m c \Delta T\\Q = m c (7 - 4)\\Q = 3 m c

Case 2 :

m = mass of the metal

c = specific heat of the metal

\Delta T = Change in temperature = 19 - 7 = 12 C

Amount of heat required for the above change of temperature is given as

Q' = m c \Delta T\\Q' = m c (12)\\Q' = (4)(3 m c)\\Q' = 4Q

Hence the correct choice is

4Q

6 0
3 years ago
Read 2 more answers
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