For the swimmer to go straight the sin component of his velocity should cancel the river velocity.
So, we have θ
This angle θ is the angle shall the swimmer point upstream from the shore.
0.32 = 0.85 sin[/tex]θ
θ =
The velocity of swimmer across the river is given by cos componet of his velocity
v = 0.85 cosθ = 0.85 cos 22 = 0.79 m/s
Answer:
Low-temperature blackbody
Explanation:
There are 3 types of blackbody temperatures.
Low-temperature blackbody
High temperature extended area blackbody
High-temperature cavity blackbody
A Low-temperature blackbody is a type of black body radiation that has the range of -40° C to 175° C, typically between 233 K and 448 K. A perfect fit for the temperature range mentioned in the question, "a few hundred Kelvin". Therefore, it's the kind of blackbody temperature that the object would emit.
<em> In a refracting telescope </em><u><em>convex lens</em></u><em> forms the image.
</em>
<u>Answer:</u> <em>c. Convex mirror</em>
<u>Explanation:</u>
Telescope is an instrument used for magnification of distant objects. The convex lenses objective and eyepiece are the two parts of a refracting telescope.
Objective has a greater focal length when compared with the eyepiece. Image of a distant object is formed at the second focal point of the objective. This image is magnified by the eyepiece.
The objective and eyepiece lenses can only produce an inverted image since they both are convex lenses. The function of producing a final erect image is performed by a pair of inverting lenses.