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Citrus2011 [14]
3 years ago
5

A force of 900 N pushes a wedge 0.10 m into a log. If the work done on the log is 50 J, what is the efficiency of the wedge?

Physics
1 answer:
Anna [14]3 years ago
8 0

Answer:

55.56%

Explanation:

We'll begin by calculating the work done in pushing the wedge. This can be obtained as follow:

Force (F) = 900 N

Distance (s) = 0.1 m

Workdone (Wd) =..?

Wd = F × s

Wd = 900 × 0.1

Wd = 90 J

Finally, we shall determine the efficiency. This can be obtained as follow:

Work output = 50 J

Work input = 90 J

Efficiency =?

Efficiency = work output / work input

Efficiency = 50 / 90 × 100

Efficiency = 55.56%

Thus, the efficiency is 55.56%

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Option B

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A projectile is launched from ground level to the top of a cliff which is 195 m away and 155 m high. If the projectile lands on
muminat

Answer:

66.02m/s

Explanation:

the equation describing the distance covered in the horizontal direction is

x=ucos\alpha t-(1/2)gt^{2} but the acceleration in the horizontal path is zero, hence we have

x=ucos\alpha t

Since the horizontal distance covered is 155m at 7.6secs, we have ucos\alpha =\frac{155}{7.6} \\ucos\alpha =20.38.............equation 1

Also from the vertical path, the distance covered is expressed as

y=usin\alpha t-(1/2)gt^{2}

since the horizontal distance covered in 7.6secs is 195m, then we have

y=usin\alpha t-(1/2)gt^{2}\\y=7.6usin\alpha -4.9(7.6)^{2}\\478.02=7.6usin\alpha \\usin\alpha =62.9...........equation 2

Hence if we divide both equation 1 and 2 we arrive at

\frac{usin\alpha }{ucos\alpha } =\frac{62.9}{20.38} \\tan\alpha =3.08\\\alpha =tan^{-1}(3.08)\\\alpha =72.02^{0}\\

Hence if we substitute the angle into the equation 1 we have

ucos72.02=20.38\\u=66.02m/s

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3 0
4 years ago
3. A large crane lifts a 25,000 kg mass in the air. The amount of work that must be done by the
andreev551 [17]

\mathfrak{\huge{\orange{\underline{\underline{AnSwEr:-}}}}}

Actually Welcome to the concept of Efficiency.

Here we can see that, the Input work is given as 2.2 x 10^7 J and the efficiency is given as 22%

The efficiency is => 22% => 22/100.

so we get as,

E = W(output) /W(input)

hence, W(output) = E x W(input)

so we get as,

W(output) = (22/100) x 2.2 x 10^7

=> W(output) = 0.22 x 2.2 x 10^7 => 0.484 x 10^7

hence, W(output) = 4.84 x 10^6 J

The useful work done on the mass is 4.84 x 10^6 J

5 0
3 years ago
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Answer:

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A chemical reaction is a change that yields the formation of new substances (products), due to the rearrangements of the atoms of the reactants.

In a very simple form, you can represent a chemical reaction by the general equation:

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Which means that some elements or compounds, those in the reactant side of the equation, undergo a change in which some chemical bonds are broken, the atoms separate from the original substances and combine into a new arrangement in which they form one or more different substances (products).

The option B), that the table dissapeared is not a clear evidence of a chemical change because it could have been dissolved, which is a physical change.

Also, the option C), that there was a color change, cannot be cited as an evidence of a chemical reaction, since the color is a physical property.

As for the option D, that there was a change in mass, is not a viable option, since mass cannot change either with a chemical or physical change.

3 0
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