Answer:
the correct answer is reduce friction
1) According to the law of conservation of momentum ..
<span>Horiz recoil mom of gun (M x v) = horiz. mon acquired by shell (m x Vh) </span>
<span>1.22^6kg x 5.0 m/s = 7502kg x Vh </span>
<span>Vh = 1.22^6 x 5 / 7502 .. .. Vh = 813 m/s </span>
<span>Barrel velocity V .. .. cos20 = Vh / V .. ..V = 813 /cos20 .. .. ►V = 865 m/s </span>
<span>2) Using the standard range equation .. R = u² sin2θ /g </span>
<span>R = 865² x sin40 / 9.80 .. .. ►R = 49077 m .. (49 km)</span>
Answer: 183.8Hz
Explanation:
Given that,
wavelength of sound (λ) = 1.85 m
frequency of the sound (F) = ?
Recall that the speed of sound (V) in air is a constant with a value of 340m/s
So, apply the formula
V = F λ
340 m/s = F x 1.85 m
F = 340m/s / 1.85m
F = 183.8Hz
Thus, the frequency of the sound that is
generated is 183.8 hertz
I am not sure of the answer but I think that the answer is a
Answer:
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