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3 years ago

If f(x) = 3(x + 4), find f(2). 729 243 81 18

Mathematics

2 answers:

bonufazy [111]3 years ago

7 0

The answer is 18.

Just replace the x with 2

Serga [27]3 years ago

4 0

Answer:

f(2) = 18

Option 4 is correct

Step-by-step explanation:

Given: f(x)=3(x+4)

To find: f(2)

The given function is linear function with variable x to find the value of function at x=2

So, put x=2 into the function and simplify it

f(x) = 3(x+4)

f(2) = 3(2+4)

f(2) = 3(6) [ multiply 3 and 6 = 18]

f(2) = 16

Hence, The value of f(2) is 18 of the given function.

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vampirchik [111]

Answer:

The shape is not there so i can not solve it

Step-by-step explanation:

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3 years ago

Mapoela walks 2 km 30 minutes. At that rate, how far could she walk in 1 ½ hours

kogti [31]

Answer:

Step-by-step explanation:

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2 years ago

A ball is thrown into the air from a height of 4 feet at time t = 0. The function that models this situation is h(t) = -16t2 + 6

katrin2010 [14]

Answer:

Part a) The height of the ball after 3 seconds is $49\ ft$

Part b) The maximum height is 66 ft

Part c) The ball hit the ground for t=4 sec

Part d) The domain of the function that makes sense is the interval

[0,4]

Step-by-step explanation:

we have

$h(t)=-16t^{2} +63t+4$

Part a) What is the height of the ball after 3 seconds?

For t=3 sec

Substitute in the function and solve for h

$h(3)=-16(3)^{2} +63(3)+4=49\ ft$

Part b) What is the maximum height of the ball? Round to the nearest foot.

we know that

The maximum height of the ball is the vertex of the quadratic equation

Convert the function into a vertex form

$h(t)=-16t^{2} +63t+4$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$h(t)-4=-16t^{2} +63t$

Factor the leading coefficient

$h(t)-4=-16(t^{2} -(63/16)t)$

Complete the square. Remember to balance the equation by adding the same constants to each side

$h(t)-4-16(63/32)^{2}=-16(t^{2} -(63/16)t+(63/32)^{2})$

$h(t)-(67,600/1,024)=-16(t^{2} -(63/16)t+(63/32)^{2})$

Rewrite as perfect squares

$h(t)-(67,600/1,024)=-16(t-(63/32))^{2}$

$h(t)=-16(t-(63/32))^{2}+(67,600/1,024)$

the vertex is the point (1.97,66.02)

therefore

The maximum height is 66 ft

Part c) When will the ball hit the ground?

we know that

The ball hit the ground when h(t)=0 (the x-intercepts of the function)

$h(t)=-16t^{2} +63t+4$

For h(t)=0

$0=-16t^{2} +63t+4$

using a graphing tool

The solution is t=4 sec

see the attached figure

Part d) What domain makes sense for the function?

The domain of the function that makes sense is the interval

[0,4]

All real numbers greater than or equal to 0 seconds and less than or equal to 4 seconds

Remember that the time can not be a negative number

6 0

3 years ago

Which equation is modeled by the graph? Using the equation, about how many more cars are in the deck at 9:00 a.m. than at 8:30 a

omeli [17]

The correct answer is Choice A.

You can see from the graph that the y-intercept is 50 because it cross on the left at 50.

To find the slope, we can use the following two points (0, 50) and (20, 110). This will give a slope of 3.

Put the 50 and 3 together and you will have the equation:
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6 0

3 years ago

Read 2 more answers

I have no idea plz help

BartSMP [9]

Where is the question?

3 0

3 years ago