Answer:
a) Attached
b) P=0.60
c) P=0.80
d) The expected flight time is E(t)=122.5
Step-by-step explanation:
The distribution is uniform between 1 hour and 50 minutes (110 min) and 135 min.
The height of the probability function will be:
Then the probability distribution can be defined as:
![f(t)=\frac{1}{25}=0.04 \,\,\,\,\\\\t\in[110,135]](https://tex.z-dn.net/?f=f%28t%29%3D%5Cfrac%7B1%7D%7B25%7D%3D0.04%20%5C%2C%5C%2C%5C%2C%5C%2C%5C%5C%5C%5Ct%5Cin%5B110%2C135%5D)
b) No more than 5 minutes late means the flight time is 125 or less.
The probability of having a flight time of 125 or less is P=0.60:
c) More than 10 minutes late means 130 minutes or more
The probability of having a flight time of 130 or more is P=0.80:
d) The expected flight time is E(t)=122.5
B and F because they would be multiplied by 100, which would move the digits two times to the right.
I think its 10 boxes per minute but i could be wrong..
Answer:
... you <u>add</u> the exponents
Step-by-step explanation:
An exponent is a way of showing repeated multiplication. For example, ...
x^2 means x·x
and
x^3 means x·x·x
If we multiply these two expressions together, we get ...
(x^2)·(x^3) = (x·x)·(x·x·x) = x·x·x·x·x
This is a product in which x appears as a factor 5 times, so we can write it using an exponent as ...
x·x·x·x·x = x^5
___
That is, when we multiply the expressions, we add the numbers of times the factor appears in the product:
2 + 3 = 5
x^2 · x^3 = x^(2+3) = x^5
Answer:
48 mph
Step-by-step explanation:
First we need to find the distance from Elkhart to Chicago. Toledo to Elkhart is 136 miles and Toledo to Chicago 244 miles.
So the distance from Elkhart to Chicago can be calculated, since Chicago is farther from Toledo than Elkhart, as: distance(Toledo to Chicago) - distance(Toledo to Elkhart). These distances are given in the problem, so the distance from Elkhat to Chicago is: 244 miles - 136 miles = 108 miles.
This problem basically wants to know the slowest you can be yet still ariving on time. If you are the minimum speed, you will arrive in Chicago exactly at 10:30 A.M. So you have 2 hours and 15 minutes(10:30 A.M - 8.15A.M.) to drive 108 miles.
15 minutes is a fourth of a hour, so you have 2.25hours to go through 108 miles.
The minimum speed you must maintain is 108mph/2.25h = 48mph.
