The function that has a vertex on the y-axis is f(x) = (x - 2)(x + 2)
<h3>How to determine the function?</h3>
For a function to have its vertex on the y-axis, then the coordinate of the vertex must be:
(h,k) = (0,y)
A quadratic function is represented as:
f(x) = (x - h)^2 + k
So, we have:
f(x) = (x - 0)^2 + k
Evaluate
f(x) = x^2 + k
From the list of options, we have:
f(x) = (x - 2)(x + 2)
Expand
f(x) = x^2 - 4
Hence, the function that has a vertex on the y-axis is f(x) = (x - 2)(x + 2)
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Answer:
m = - 1
Step-by-step explanation:
9m + 13 = 4
subtract 13 from both sides
9m = 4 - 13
9m = - 9
divide both sides by 9
m = - 1 (negative 1)
Answer:
49 cm²
Step-by-step explanation:
The volume (V) of a cube is calculated as
V = s³ ← s is the length of the side, thus
s³ = 343 ( take the cube root of both sides )
s =
= 7, thus
area of base = s² = 7² = 49 cm²
Answer:
C
Step-by-step explanation:
first of all, the correct factorization is
y = (x - 3)(x + 6)
because when we do the multiplication
y = x² + 6x - 3x - 18 = x² + 3x - 18
and then, the factorization tends us also directly the zero points, because y is only 0, when one of the factors is 0.
so, either x-3 or x+6 has to be 0 to make the whole expression 0.
and that is only for x=3 or x=-6
Answer:
25% increase
Step-by-step explanation: