Answer:
a) 23.2 e V
b) energy of the original photon is 36.8 eV
Explanation:
given,
energy at ground level = -13.6 e V
energy at first exited state = - 3.4 e V
A photon of energy ionized from ground state and electron of energy K is released.
h ν₁ - 13.6 = K
K combine with photon in first exited state giving out photon of energy
= 26.6 e V
h c = 6.626 × 10⁻³⁴ × 3 × 10⁸ = 12400 e V A°
K + ( 3.4 ) = 26.6 e V
a) energy of free electron
K = 26.6 - 3.4 = 23.2 e V
b) energy of the original photon
h ν₁ - 13.6 = K
h ν₁ = 23.2 + 13.6
= 36.8 e V
energy of the original photon is 36.8 eV
Answer: Energy consumption and sustainability is important so that it remain available for future generation.
Explanation:
1. The home furnaces are likely to require fuel like coal, which will directly emit carbon dioxide and carbon monoxide gases. These should be replaced with the electrical furnaces. The old or more power consuming air conditioners should be replaced with new ones.
2. The water heaters should be tankless so their capacity to heat more water could be possible. The water heaters should be electricity saving.
3. Washer and dryers should be water savy and electricity savy. A front-loading washing machine is useful energy saver.
4. The LED lights are more electricity saving than conventional bulbs. Halogen lights are also electricity saving.
Answer:
The velocity of the star is 0.532 c.
Explanation:
Given that,
Wavelength of observer = 525 nm
Wave length of source = 950 nm
We need to calculate the velocity
If the direction is from observer to star.
From Doppler effect
![\lambda_{0}=\sqrt{\dfrac{c+v}{c-v}}\times\lambda_{s}](https://tex.z-dn.net/?f=%5Clambda_%7B0%7D%3D%5Csqrt%7B%5Cdfrac%7Bc%2Bv%7D%7Bc-v%7D%7D%5Ctimes%5Clambda_%7Bs%7D)
Put the value into the formula
![525=\sqrt{\dfrac{c+v}{c-v}}\times950](https://tex.z-dn.net/?f=525%3D%5Csqrt%7B%5Cdfrac%7Bc%2Bv%7D%7Bc-v%7D%7D%5Ctimes950)
![\dfrac{c+v}{c-v}=(\dfrac{525}{950})^2](https://tex.z-dn.net/?f=%5Cdfrac%7Bc%2Bv%7D%7Bc-v%7D%3D%28%5Cdfrac%7B525%7D%7B950%7D%29%5E2)
![\dfrac{c+v}{c-v}=0.305](https://tex.z-dn.net/?f=%5Cdfrac%7Bc%2Bv%7D%7Bc-v%7D%3D0.305)
![c+v=0.305\times(c-v)](https://tex.z-dn.net/?f=c%2Bv%3D0.305%5Ctimes%28c-v%29)
![v(1+0.305)=c(0.305-1)](https://tex.z-dn.net/?f=v%281%2B0.305%29%3Dc%280.305-1%29)
![v=\dfrac{0.305-1}{1+0.305}c](https://tex.z-dn.net/?f=v%3D%5Cdfrac%7B0.305-1%7D%7B1%2B0.305%7Dc)
![v=−0.532c](https://tex.z-dn.net/?f=v%3D%E2%88%920.532c)
Negative sign shows the star is moving toward the observer.
Hence, The velocity of the star is 0.532 c.
Answer:
Fₓ = 0,
= 0 and
<em> = - 3.115 10⁻¹⁵ N</em>
Explanation:
The magnetic force given by the expression
F = q v xB
the bold are vectors, the easiest analytical way to determine this force in solving the determinant
F = 1.6 10⁻¹⁵ [ i( 0-0) + j (0-0) + k^( 5.8 0.60 - 0.81 67) ]
F =i^0 + j^0
- k^ 3.115 10⁻¹⁵ N
Fₓ = 0
= 0
<em> = - 3.115 10⁻¹⁵ N</em>