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mash [69]
3 years ago
13

Suppose the earth is shaped as a sphere with radius 4,0004,000 miles and suppose it rotates once every 24 hours. How many miles

along the equator does it rotate each hour? (approximation is acceptable)
Physics
1 answer:
Alenkinab [10]3 years ago
8 0

Answer:

1047 miles

Explanation:

The radius of the Earth is

r = 4000 (miles)

So its circumference, which is the total length of the equator, is given by

L=2\pi r= 2\pi(4000)=25133 mi

Now we know that the Earth rotates once every 24 hours. So the distance through which the equator moves in one hour is equal to its total length divided by the number of hours, 24:

L' = \frac{25133 mi}{24h}=1047 mi

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A machine which has an energy loss of 10% will have efficiency of​
larisa [96]

Answer:

90%

Explanation:

if you lose 10% of a 100 you get 90

6 0
2 years ago
Professional Application. A 96 kg football player catches a 0.900 kg ball with his feet off the ground with both of them moving
Zarrin [17]

To solve this problem it is necessary to apply the equations related to the conservation of momentum.

This definition can be expressed as

m_1u_1+m_2u_2 = (m_1+m_2)V_f

Where

m_{1,2} = Mass of each object

u_{1,2} = Initial Velocity of each object

V_f= Final velocity

Rearranging the equation to find the final velocity we have,

V_f = \frac{m_1u_1+m_2u_2}{(m_1+m_2)}

Our values are given as

m_1 = 96Kg\\m_2 = 0.9Kg\\u_1 = 6.3m/s\\u_2 = 27.4m/s

Replacing we have,

V_f = \frac{(96)(6.3)+(0.9)(27.4)}{(96+0.9)}

V_f = 6.4959m/s

Therefore the final velocity is 6.5m/s

3 0
3 years ago
In which region of the electromagnetic spectrum is most of earth's outgoing terrestrial radiation?
Bond [772]
The answer is Infrared.  The infrared of the electromagnetic spectrum is most of earth's outgoing terrestrial radiation.  <span>Earth is the hot body with temperature of 30 degrees on the average.</span>
6 0
3 years ago
A motorcycle accelerated from 10 metre per second to 30 metre per second in 6 seconds. How far did it travel in this time ?
Ber [7]
U=10 m/s
v=30 m/s
t=6 sec

therefore, a=(v-u)/t
                   =(30-10)/6
                   =(10/3) ms^-2

now, displacement=ut+0.5*a*t^2
                              =60+ 0.5*(10/3)*36
                              =120 m
And you can solve it in another way:

v^2=u^2+2as
or, s=(v^2-u^2)/2a
       =(900-100)/6.6666666.......
       =120 m

7 0
3 years ago
Calculate the air pressure in the pressurized tank, if h1 = 0. 18 m, h2 = 0. 2m and h3 = 0. 25m. The density of the mercury, wat
fomenos

The air pressure in the pressurized tank will be 24014.88 N/m²,196.2 N/m²,2084.625  N/m².

<h3 /><h3>What is pressure?</h3>

The force applied perpendicular to the surface of an item per unit area across which that force is spread is known as pressure.

It is denoted by P. The pressure relative to the ambient pressure is known as gauge pressure.

Pressure is found as the product of the density,acceleraton due to gravity and the height.

P₁=ρ₁gh₁

P₁=13,600 kg/m³×9.81 (m/s²)×0.18 m

P₁=24014.88 N/m²

P₂=ρ₂gh₂

P₂= 1000 kg/m³×9.81 (m/s²)×00.2 m

P₂=196.2 N/m²

P₃=ρ₃gh₃

P₃=850 kg/m³×9.81 (m/s²)×0.25

P₃=2084.625  N/m²

Hence,the air pressure in the pressurized tank will be 24014.88 N/m²,196.2 N/m²,2084.625  N/m².

To learn more about the pressure refer to the link;

brainly.com/question/356585

#SPJ4

6 0
1 year ago
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