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mash [69]
3 years ago
13

Suppose the earth is shaped as a sphere with radius 4,0004,000 miles and suppose it rotates once every 24 hours. How many miles

along the equator does it rotate each hour? (approximation is acceptable)
Physics
1 answer:
Alenkinab [10]3 years ago
8 0

Answer:

1047 miles

Explanation:

The radius of the Earth is

r = 4000 (miles)

So its circumference, which is the total length of the equator, is given by

L=2\pi r= 2\pi(4000)=25133 mi

Now we know that the Earth rotates once every 24 hours. So the distance through which the equator moves in one hour is equal to its total length divided by the number of hours, 24:

L' = \frac{25133 mi}{24h}=1047 mi

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A capacitor has plates of area 1.64 * 10 ^ - 3 * m ^ 2 . To create a capacitance of 2.38 * 10 ^ - 9 * F , how far apart should t
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6.1 * 10^-6

Explanation:

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A ball is thrown into the air with 100 J of kinetic energy, which is transformed to gravitational potential energy
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Answer:

Air resistance

Explanation:

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When you float an ice cube in water, you notice that 90% of it is submerged beneath the surface. Now suppose you put the same ic
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option (c)

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6 0
3 years ago
A wildebeest and chicken participate in a race over a 2.00km long course. the wildebeest travels at a speed of 16.0m/s and chick
Nezavi [6.7K]

Answer:

(a)  The distance of the chicken from the finish line is 62.5 m

(b) The stationary time of the wildebeest is 675 s

Explanation:

Given;

total distance traveled by wildebeest and chicken, d = 2 km = 2000 m

speed of the wildebeest, v_w = 16 m/s

speed of the chicken, v_c = 2.5 m/s

Time for wildebeest to finish the race without stopping, 2000 / 16 = 125 s

Time for chicken to finish the race without stopping, 2000/2.5 = 800 s

(b) for how long in time (in s) was the wildebeest stationary?

t(stationary) = t(chicken) - t(wildebeest)

t = 800s - 125 s

t = 675 s

(a) how far (in m) is the chicken from the Finish Line when the wildebeest resume the race?

The time taken for the wildebeest to run 1.6 km (1600 m) is given by;

t = 1600 / 16 = 100 s

The total time spent by the wildebeest before it resumed the race = stationary time + 100s

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Distnace traveled by the chicken when the wildebeest resumed the race = 2.5m/s x 775s = 1937.5 m

Thus, the distance of the chicken from the finish line = 2000 m -  1937.5 m

the distance of the chicken from the finish line = 62.5 m

7 0
3 years ago
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