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Tcecarenko [31]
3 years ago
12

Can u read a ruler it's very hard

Physics
1 answer:
iris [78.8K]3 years ago
8 0

Answer:

A. 1 inch

B. 1/2 inch

C. 3/4 inch

D. 1/8 inch

E. 1 7/8 inch

F. 1 1/2 inch

G. 3 1/15 inch

H. 2 5/8 inch

I. 2 1/4 inch

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If there is a 25 [lbs] of force acting on a 5 [lbs] of mass, what is the acceleration of that mass?
mihalych1998 [28]

Answer:

f = 25 lbs

m = 5 lbs

a =?

f = ma

25 = 5 a( divide both sides by 5)

a = 5(lbs)

5 0
2 years ago
A foot player runs 1.6m/s and has a KE of 790 J. What is his mass?
Mariana [72]
The equation for kinetic energy is,

Ke = (1/2)mv^2.

You're given a kinetic energy of 790 joules, and a speed of 1.6 m/s. Plugging these values into the equation, we get,

790 = (1/2)(1.6)^2(m).

Solving for m, we get,

m = (790)/(0.5(1.6)^2).

I'll let you crunch out those numbers for yourself :D

If you have any questions, feel free to ask. Hope this helps!
3 0
3 years ago
What is an example of transparent
nataly862011 [7]

Answer:

When something is transparent, it means that it allows light to pass through or is see-through . For example:

1) glass

2) air

3) some plastics

7 0
3 years ago
Read 2 more answers
Please help need this asap
NikAS [45]

Answer:

A)  350 N

B)  58.33 N

C)  35 kg

D)  35 kg

Explanation:

If we use that g = 10 m/s^2, then the acceleration of gravity on the Moon will be 10/6 m/s^2 = 5/3 m/s*2

The weight of the object on Earth is given by:

Weight = mass * g = 35 * 10 = 350 N

The weight of the object on the Moon:

Weight = mass * gmoon = 35 * 5/3 = 58.33 N

The mass of the object on Earth is 35 kg

The mass of the object on the Moon is exactly the same as on the Earth (35 kg) since the mass is a quantity inherent to the object and not to its location.

3 0
2 years ago
A small sphere has a harge of 9uC and other small sphere has a charge of 4uC.
Helga [31]

Answer:

Electrical force, F = 90 N

Explanation:

It is given that,

Charge on sphere 1, q_1=9\ \mu C=9\times 10^{-6}\ C

Charge on sphere 2, q_1=4\ \mu C=4\times 10^{-6}\ C

Distance between two spheres, d = 6 cm = 0.06 m

Let F is the electrical force between them. It is given by the formula of electric force which is directly proportional to the product of charges and inversely proportional to the square of distance between them such that,

F=k\dfrac{q_1q_2}{d^2}

F=9\times 10^9\times \dfrac{9\times 10^{-6}\times 4\times 10^{-6}}{(0.06)^2}

F = 90 N

So, the electrical force between them is 90 N. Hence, this is the required solution.

7 0
3 years ago
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