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Leno4ka [110]
3 years ago
15

Gravity is the attractive pull between two objects that have mass. The strength of the gravitational distance. As distance betwe

en the objects increases, the force of gravity decreases. If the distance
one-fourth as strong as before. Which one of the graphs best represents the relationship between
pull is doubled,
gravity and distance. depends
on mass and the force of gravity is
A. A
B. B
C. C
D. D

Sorry for the bad picture right now i dont have to take a nice picture

Physics
1 answer:
Mumz [18]3 years ago
4 0

Graph A best represents the relationship between pull is doubled, gravity and distance. depends on the mass and the force of gravity. Option A is correct.

<h3>What is Newton's law of gravity?</h3>

Newton's law of gravity states that each particle having mass in the universe attracts each other particle with a force known as the gravitational force.

The expression for the gravitational force is given as;

\rm F = G\frac{Mm}{r^2}

Gravitational force is proportional to the product of the masses of the two bodies and inversely proportional to the square of their distance.

Decreasing the distance would increase the gravity of the planet.

Gravity is the attraction force that draws two mass-containing objects together. the gravitational distance's strength.

The force of gravity weakens as the distance between the items rises. if the separation is just one-fourth as great as previously. In the graph, the link between pull and doubled is best represented by A.

Hence option A is correct.

To learn more about Newton's law of gravity refer to the link;

brainly.com/question/13428472

#SPJ1

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Answer:

they both weight the same

Explanation:

they both weigh one kilo so they are the same

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Two girls,(masses m1 and m2) are on roller skates and stand at rest, close to each other and face-to-face. Girl 1 pushes squarel
Arturiano [62]

Answer:

\vec{v}_1 = -\frac{\vec{v}_2m_2}{m_1}

Explanation:

The center of mass of the system (two girls) is constant, as the velocity of the center of mass of the system is also constant.

\vec{v}_{cm} = \frac{m_1\vec{v}_1 + m_2\vec{v}_2}{m_1 + m_2}

<u>The initial velocity of the system is zero, since both girls are at rest.</u> So the velocity of the total system at any point should be zero as well.

0 = \frac{m_1\vec{v}_1 + m_2\vec{v}_2}{m_1 + m_2}\\\vec{v}_1 = -\frac{\vec{v}_2m_2}{m_1}

This is true, because there is no friction between the girls and the ground. Otherwise, the velocity of the center of mass wouldn't be constant.

5 0
3 years ago
To initiate a nuclear reaction, an experimental nuclear physicist wants to shoot a proton into a 5.50-fm-diameter 12C nucleus. T
Crazy boy [7]

Answer:

The value is  u  =  3.23 *10^{7} \  m/s

Explanation:

From the question we are told that

   The diameter of the nucleus is d =  5.50 \ fm = 5.50 *10^{-15} \  c

   The charge of the proton that makes up the nucleus is  Q_2 = \frac{12}{2}  * 1.60 *10^{-19} =9.6*10^{-19} \ C

    The energy to be impacted is  KE_f  =  2.30 \  MeV  =  2.30 *10^{6} \  eV =   2.30 *10^{6}  *  1.60 *10^{-19} = 3.68*10^{-13} \  J

Generally the radius of the nucleus is mathematically represented as

         r  =  \frac{d}{2}

=>      r  =  \frac{5.50 *10^{-15}}{2}

=>      r  =  2.75 *10^{-15} \  m

Generally from the law energy conservation we have that

     Initial \  total  \  energy \ of the \  proton =  final \  total  \  energy \ of the \  proton

i.e

    T_i  =  T_f

Here

   T_i  =  KE_i + PE_i

Here KE_i is the initial kinetic energy which is mathematically represented as

       KE_I  =  \frac{1}{2}  *  m * u ^2

Here  PE_i is the initial potential energy of the proton and the value is  0 J given that the proton is moving

Also  T_f is mathematically represented as

         T_f  =  KE_f + PE_f

Here  

        PE_f  is the final potential energy which is mathematically represented as

         PE_f  = \frac{k * Q_1 * Q_2}{r}

Here Q_1 is the charge on the proton with a value of Q_1 =  1.60 *10^{-19} \  C

So

        PE_f  = \frac{9*10^{9} *(1.60 *10^{-19} ) * ( 9.6 *10^{-19})}{ 2.75 *10^{-15}}

=>     PE_f  = 5.027 *10^{-13 } \  J

So  

         KE_i + PE_i  =  KE_f + PE_f

=>       \frac{1}{2}  *  m * u ^2 +0  =  3.68*10^{-13} + 5.027 *10^{-13 }

Here m is the mass of the moving proton with value m =  1.67*10^{-27} \  kg

So

       \frac{1}{2}  *  1.67*10^{-27}  * u ^2 +0  =  3.68*10^{-13} + 5.027 *10^{-13 }

=>      u  =  \sqrt{\frac{3.68*10^{-13} + 5.027 *10^{-13 }}{0.5  *  1.67*10^{-27}} }

=>       u  =  3.23 *10^{7} \  m/s

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3 years ago
A frictionless cart attached to a spring vibrates with amplitude A. Part A Determine what fraction of the total energy (Etot) of
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Answer:

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Explanation:

the solution is in the attached Word file

Download docx
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3 years ago
WILL MARK BRANLIEST!
Savatey [412]
I would go with c due the fact that water has tendencies to flow, meaning it will runoff and majority of the water will run off, it couldn’t be a because the fact that the grass and plant will absorb what they need. D clearly is too vague for such a question. B would be the only contesting answer but I feel c is the stronger choice because evaporations is a longer process and because of that only little amounts of water will evaporate while majority of it will become runoff due to hills, mountains, storm drains, slopes, etc.
4 0
3 years ago
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