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Leno4ka [110]
2 years ago
15

Gravity is the attractive pull between two objects that have mass. The strength of the gravitational distance. As distance betwe

en the objects increases, the force of gravity decreases. If the distance
one-fourth as strong as before. Which one of the graphs best represents the relationship between
pull is doubled,
gravity and distance. depends
on mass and the force of gravity is
A. A
B. B
C. C
D. D

Sorry for the bad picture right now i dont have to take a nice picture

Physics
1 answer:
Mumz [18]2 years ago
4 0

Graph A best represents the relationship between pull is doubled, gravity and distance. depends on the mass and the force of gravity. Option A is correct.

<h3>What is Newton's law of gravity?</h3>

Newton's law of gravity states that each particle having mass in the universe attracts each other particle with a force known as the gravitational force.

The expression for the gravitational force is given as;

\rm F = G\frac{Mm}{r^2}

Gravitational force is proportional to the product of the masses of the two bodies and inversely proportional to the square of their distance.

Decreasing the distance would increase the gravity of the planet.

Gravity is the attraction force that draws two mass-containing objects together. the gravitational distance's strength.

The force of gravity weakens as the distance between the items rises. if the separation is just one-fourth as great as previously. In the graph, the link between pull and doubled is best represented by A.

Hence option A is correct.

To learn more about Newton's law of gravity refer to the link;

brainly.com/question/13428472

#SPJ1

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A horizontal desk surface measures 1.7 m by 1.0 m. If the Earth's magnetic field has magnitude 0.42 mT and is directed 68° below
AlexFokin [52]

Answer:

The magnetic flux through the desk surface is 6.6\times10^{-4}\ T-m^2.

Explanation:

Given that,

Magnetic field B = 0.42 T

Angle =68°

We need to calculate the magnetic flux

\phi=BA\costheta

Where, B = magnetic field

A = area

Put the value into the formula

\phi=0.42\times10^{-3}\times1.7\times1.0\cos22^{\circ}

\phi=0.42\times10^{-3}\times1.7\times1.0\times0.927

\phi=6.6\times10^{-4}\ T-m^2

Hence, The magnetic flux through the desk surface is 6.6\times10^{-4}\ T-m^2.

3 0
3 years ago
A rowboat has a momentum of 241.5 kg*m/s. if the rowboat has a mass of 115kg, what its it's speed?
Lera25 [3.4K]
Momentum = mass*velocity(or speed)

241.5 kg*m/s = 115 kg * v
v = 241.5 kg*m/s / 115 kg = 2.10 m/s
6 0
3 years ago
Sasha lifts a couch 8.2 meters from the ground floor of her house to the attic. If the couch has a mass of 120 kg, what is the g
gavmur [86]

As we know that gravitational potential energy is given by

U = mgH

here we have

m = mass = 120 kg

g = 9.81 m/s^2

h = height = 8.2 m

now from above formula

U = 120kg (9.81 m/s^2) (8.2 m)

U = 9653.04 J

so above is the gravitational potential energy of the couch

4 0
3 years ago
Read 2 more answers
An electron is accelrated by a unifor electric field (1000v/m) pointing vertically upward. Use energy methods to get the magnitu
ExtremeBDS [4]

Explanation:

In the given situation two forces are working. These are:

1) Electric force (acting in the downward direction) = qE

2) weight (acting in the downward direction) = mg

Therefore, work done by all the forces = change in kinetic energy

Hence, qE \times S + mg \times S = 0.5 \times mv^{2}

     1.6 \times 10^{-19} \times 1000 + 9.1 \times 10^{-31} \times 9.8 \times (\frac{0.10}{100}) = 0.5 \times 9.1 \times 10^{-31} \times v^{2}

It is known that the weight of electron is far less compared to electric force. Therefore, we can neglect the weight  and the above equation will be as follows.

   (1.6 \times 10^{-19} \times 1000) \times (\frac{0.10}{100}) = 0.5 \times 9.1 \times 10^{-31} \times v^{2&#10;}

         v = sqrt{\frac{1.6 \times 10^{-19}}{(0.5 \times 9.1 \times 10^{-31})}

           = 592999 m/s

Since, the electron is travelling downwards it means that it looses the potential energy.

8 0
3 years ago
Coherent light of wavelength 525 nm passes through two thin slits that are 4.15×10^(−2) mm apart and then falls on a screen 7
IRINA_888 [86]

A) 4.7 cm

The formula for the angular spread of the nth-maximum from the central bright fringe for a diffraction from two slits is

sin \theta=\frac{n \lambda}{d}

where

n is the order of the maximum

\lambda is the wavelength

a is the distance between the slits

In this problem,

n = 5

\lambda=525 nm =5.25\cdot 10^{-7} m

a=4.15\cdot 10^{-2} mm=4.15\cdot 10^{-5} m

So we find

\theta=sin^{-1} (\frac{(5)(5.25\cdot 10^{-7} m)}{4.15\cdot 10^{-5} m})=3.62^{\circ}

And given the distance of the screen from the slits,

D=75.0 cm = 0.75 m

The distance of the 5th  bright fringe from the central bright fringe will be given by

y=D tan \theta = (0.75 m)tan 3.62^{\circ}=0.047 m = 4.7 cm

B) 8.1 cm

The formula to find the nth-minimum (dark fringe) in a diffraction pattern from double slit is a bit differente from the previous one:

sin \theta=\frac{(n+\frac{1}{2}) \lambda}{d}

To find the angle corresponding to the 8th dark fringe, we substitute n=8:

\theta=sin^{-1} (\frac{(8+\frac{1}{2})(5.25\cdot 10^{-7} m)}{4.15\cdot 10^{-5} m})=6.17^{\circ}

And the distance of the 8th dark fringe from the central bright fringe will be given by

y=D tan \theta = (0.75 m)tan 6.17^{\circ}=0.081 m = 8.1 cm

5 0
3 years ago
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