All categories

3 years ago

Using the law of conservation of energy, explain why an LED light is more energy efficient that an incandescent light bulb.

Chemistry

1 answer:

hjlf3 years ago

3 0

Answer:

An LED light uses one-third the energy of an incandescent bulb to produce the same amount of light.

Step-by-step explanation:

A typical 100 W incandescent bulb produces about 5 % visible light, 83 % IR radiation, and 12 % heat (it is the IR radiation that makes the bulb feel hot).

It produces about 5 J of light energy for every 100 J of energy input.

A typical LED bulb produces about 15 % visible light and 85 % heat (LEDs feel cool, because they don't produce IR radiation).

It produces about 15 J of light energy for every 100 J of energy input.

Thus, an LED light is about three times as efficient at converting electrical energy into light

You might be interested in

A substance that increases the rate of a chemical reaction is called a(n) _____. answer

rodikova [14]

Catalyst increases the rate of a chemical reaction

3 0

3 years ago

Read 2 more answers

A compound made of two elements, iridium (Ir) and oxygen (O), was produced in a lab by heating iridium while exposed to air. The

natima [27]

1) Compund Ir (x) O(y)

2) Mass of iridium = mass of crucible and iridium - mass of crucible = 39.52 g - 38.26 g = 1.26 g

3) Mass of iridium oxide = mass of crucible and iridium oxide - mass of crucible = 39.73g - 38.26g = 1.47g

4) Mass of oxygen = mass of iridum oxide - mass of iridium = 1.47g - 1.26g = 0.21g

5) Convert grams to moles

moles of iridium = mass of iridium / molar mass of iridium = 1.26 g / 192.17 g/mol = 0.00656 moles

moles of oxygen = mass of oxygen / molar mass of oxygen = 0.21 g / 15.999 g/mol = 0.0131

6) Find the proportion of moles

Divide by the least of the number of moles, i.e. 0.00656

Ir: 0.00656 / 0.00656 = 1

O: 0.0131 / 0.00656 = 2

=> Empirical formula = Ir O2 (where 2 is the superscript for O)

Answer: Ir O2

5 0

3 years ago

Read 2 more answers

Calcule la molaridad de una solución acuosa de ácido sulfúrico (H₂SO₄) que se preparó al mezclar, en un recipiente aforado, 4 mo

oee [108]

Considerando la definición de molaridad, la molaridad de una solución acuosa de ácido sulfúrico (H₂SO₄) es 0.5 $\frac{moles}{litro}$ .

La molaridad es una medida de la concentración de un soluto en una disolución que se define como el número de moles de soluto que están disueltos en un determinado volumen.

La molaridad de una solución se calcula dividiendo los moles del soluto por el volumen de la solución:

$Molaridad=\frac{numero de moles de soluto}{volumen}$

La Molaridad se expresa en las unidades $\frac{moles}{litro}$ .

En este caso, sabes que una solución acuosa se preparó al mezclar 4 moles del ácido con suficiente agua hasta completar 8 litros de solución. Entonces, sabes que:

número de moles de soluto= 4 moles
volumen= 8 litros

Reemplazando en la definición de molaridad:

$Molaridad=\frac{4 moles}{8 litros}$

Resolviendo:

Molaridad= 0.5 $\frac{moles}{litro}$

Finalmente, la molaridad de una solución acuosa de ácido sulfúrico (H₂SO₄) es 0.5 $\frac{moles}{litro}$ .

Aprende más:

8 0

2 years ago

Which describes a stationary reference point?

kondaur [170]

Answer: C

Explanation:

7 0

2 years ago

Madrid vs balonay soccor team why is Madrid better can u like compare it and Ik it say science and this rly is science my teache

nignag [31]

Eh I can't comment

That's y

No-one knows that I enter this site

Only a cousin knows

Cz I've got a protective family lol

4 0

2 years ago