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Ronch [10]
3 years ago
9

If you weigh 100 kg, how much would you weigh if all the water were removed from your body? A65 kg B45 kg C50 kg D35 kg

Chemistry
1 answer:
Mekhanik [1.2K]3 years ago
5 0

Answer:

B. 45k

The human body is about 60 to 70% water.

(:

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Given the reaction: A + B <--> C + D
Lady_Fox [76]

Answer:

A.) 4.0

Explanation:

The general equilibrium expression looks like this:

K = \frac{[C]^{c} [D]^{d} }{[A]^{a} [B]^{b} }

In this expression,

-----> K = equilibrium constant

-----> uppercase letters = molarity

-----> lowercase letters = balanced equation coefficients

In this case, the molarity's do not need to be raised to any numbers because the coefficients in the balanced equation are all 1. You can find the constant by plugging the given molarities into the equation and simplifying.

K = \frac{[C]^{c} [D]^{d} }{[A]^{a} [B]^{b} }                                       <----- Equilibrium expression

K = \frac{[2 M] [2 M]}{[1 M] [1 M] }                                     <----- Insert molarities

K = \frac{4}{1  }                                                <----- Multiply

K = 4                                                <----- Divide

6 0
2 years ago
White vitriol molecular formula<br>and green vitriol molecular formula??​
IgorC [24]

Answer:

<em>Green</em><em> </em><em>vitriol</em><em>-</em><em> </em><em>FeSO4·7H2O</em>

<em>white</em><em> </em><em>vitriol</em><em>-</em><em> </em><em>ZnSO₄</em>

8 0
2 years ago
Consider a cell membrane at 298K which has glucose at the concentration of 200mM inside the cell and 20 mM outside the cell, wit
OleMash [197]

Answer:

D. +5.7 kJ/mol

Explanation:

Molar free energy (ΔG) in the transportation of uncharged molecules as glucse through a cell membrane from the exterior to the interior of the cell is defined as:

ΔG = RT ln C in / C out

knowing R is 8,314472 kJ/molK; T is 298K Cin = 200mM and Cout = 20mM

ΔG = 5,7 kJ/mol

Right answer is:

D. +5.7 kJ/mol

I hope it helps!

4 0
3 years ago
According to the image, identify the number of neutrons in the most common isotope of aluminum.
wolverine [178]

Answer:

The number of neutron in the Aluminium Isotope is :

B. 14

Explanation:

Isotopes : These are the atoms which have same atomic number but have different mass number.

<u>This image shows the average atomic mass of Al element because it is in decimals</u>.

Atomic mass = 26.98154

(Note : mass number of single isotope can never be in decimals)

It is the average of mass of different isotopes of Al

Major Isotopes of _{13}^{26.98154}\textrm{Al} are :

  1. _{13}^{26}\textrm{Al}......atomic mass = 26
  2. _{13}^{27}\textrm{Al}.......atomic mass = 27

mass of Al given in image(26.98) is nearly equal to mass of 2nd isotope(27)

mass of _{13}^{26.98154}\textrm{Al}\ \approx 27

Now calculate the neutron in _{13}^{27}\textrm{Al}

Number of neutron = mass number - atomic number

                                = 27 - 13

Number of neutron = 14

(Atomic mass is same as mass number)

5 0
3 years ago
Choose the more reactive metal Te or O
kvasek [131]

Te is the answer between the two

8 0
3 years ago
Read 2 more answers
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