Answer:
Yes, Chris will score
Step-by-step explanation:
Given the function :
F(x) = - 0.05(x - 16)² + 11
Distance from goal = 25
Height of goal = 8
Scoring condition, if ball isn't blocked :
If the ball travels a distance of 25 feets towards goal and elevation of ball isn't greater than 8 feets, then Chris will score ;
Function which models ball height with respect to distance, x
Put x = 25 in the equation and se if f(x) < 8 feets
F(25) = - 0.05(25 - 16)² + 11
F(25) = - 0.05(9)² + 11
F(25) = - 0.05 * 81 + 11
F(25) = - 4.05 + 11
F(25) = 6.95 feets
Hence, Chris would score if ball isn't vlaocjed by DeShawn because the height of ball is lower than the height of the goal.
Answer:
Option A and
Step-by-step explanation:
we have
-----> equation A
This is the equation of a circle with center at the origin and radius units
-----> equation B
This is the equation of a line
we know that
The solution of the system of equations is the intersection point both graphs
using a graphing tool
The intersection points are and
see the attached figure
therefore
the x-coordinates of the solution are and
Answer:
27/35
Step-by-step explanation:
(f/g)(5) means f(5)/g(5).
So we will need to find both f(5) and g(5).
f(5) means replace x with 5 in f. This gives us 7+4×5.
Let's simplify 7+4×5:
7+4×5
7+20
27.
g(5) means replace x with 5 in g. This gives us 7×5.
Simplifying 7×5 gives us 35.
(f/g)(5)=f(5)/g(5)=27/35.
i think it would be 2 degrees every hour for 10 to 11 hours i think it would be 2 degrees
S= a(1-r ⁿ) /(1-r) & when r is < 1 & n →∞, the sum becomes S= a/(1-r)
Progression P is 2,1, 1/2,1/4,.. ==> r = 1/2
Sum of P when n--> ∞ = 2/(1-1/2) ==> S =4
Progression Q is 3,1,1/3,1/9,....==> r = 1/3
Sum of Q when n--> ∞ = 3/(1-1/3) ==> S =4.5
GIVEN THAT 4, 9/2 & X (to be calculated later is a geometric Progression, hence 9/2 - 4 = 0.5 =d (common difference , so X = 4.5+0.5 & X = 5
Sum of R =5 Then => 5= 4 /(1-r) & r=1/5
Then the sum of R = 4/(1-1/5) ==> S of R =5