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3 years ago

Using the graph provided, find f(−2)

Mathematics

2 answers:

dimulka [17.4K]3 years ago

8 0

Answer:

f(-2) = 1

Step-by-step explanation:

f(-2) means find the y value when x = -2

Going to x=-2 and going up until we hit the blue line

f(-2) = 1

lara31 [8.8K]3 years ago

3 0

Answer:

$\Large \boxed{f(-2)=1}$

Step-by-step explanation:

For f(-2), the input of the function f(x) is -2.

The input is the x value.

$x = -2$

The output is the value of y.

When x = -2 on the graph, y = 1.

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Mademuasel [1]

Answer:

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Step-by-step explanation:

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3 years ago

Simplify 2- 5/8 and -2 3/5 A. -6 33/40 B. 4- 3/8 C. 4 3/8 d. 6 33/40

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Answer:

Step-by-step explanation:

Convert mixed fraction to improper fraction.

$-2\dfrac{5}{8}*(-2\dfrac{3}{5})=\dfrac{-21}{8}*\dfrac{-13}{5}\\$

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2 years ago

Oh 9i is a root of the polynomial function f(x), which of the following must also be a root of f(x)? A. -9i B. -1/9i C. 1/9i D.

kotegsom [21]

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3 years ago

Read 2 more answers

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sineoko [7]

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3 years ago

Choose the correct answer below. A. Increasing the level of confidence has no effect on the interval. B. Increasing the level of

murzikaleks [220]

Answer:

$ME = t_{\alpha/2} \frac{s}{\sqrt{n}}$

And the width for the confidence interval is given by:

$Width =2ME=2t_{\alpha/2} \frac{s}{\sqrt{n}}$

And we want to see the effect if we increase the confidence level for a interval. On this case if we increase the confidence level then the critical value for the confidence interval $t_{\alpha/2}$ would be higher and then the width of the interval would increase. So then the best answer for this case would be:

B. Increasing the level of confidence widens the interval.

Step-by-step explanation:

Let's assume that we have a parameter of interest $\mu$ who represent for example the true mean for a population. And we can construct a confidence interval in order to estimate this parameter if we know the distribution for the statistic let's say $\bar X$ and for this particular example the confidence interval is given by:

$\bar X \pm ME$

Where ME represent the margin of error for the estimation and this margin of error is given by:

$ME = t_{\alpha/2} \frac{s}{\sqrt{n}}$

And the width for the confidence interval is given by:

$Width =2ME=2t_{\alpha/2} \frac{s}{\sqrt{n}}$

B. Increasing the level of confidence widens the interval.

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3 years ago