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astra-53 [7]
4 years ago
15

Find the distance between the points. A(3, 0) and B((8,10)

Mathematics
1 answer:
kap26 [50]4 years ago
6 0

Answer:

The distance is 5 square root of 5, or if it asks in decimal form it would be 11.180.

Step-by-step explanation:

To find the distance between any points, you must use the distance formula. When you plug in the points given, you end up with 11.180. I hope this helps!

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Is 8000 meters greater than 9 kilometers?
mrs_skeptik [129]

Answer:

no

Step-by-step explanation:

6 0
1 year ago
Read 2 more answers
(5x4 + 5x3 + 4x - 9) + (2x4 + 7x2 + 2x + 14)
ladessa [460]

Answer:

7x⁴ + 5x³ + 7x² + 6x + 5

Step-by-step explanation:

The given expression is

(5x4 + 5x3 + 4x - 9) + (2x4 + 7x2 + 2x + 14)

The first step is to open the brackets by multiplying each term inside each bracket by the term outside each bracket. Since the term outside each bracket is 1, the expression becomes

5x⁴ + 5x³ + 4x - 9 + 2x⁴ + 7x² + 2x + 14

We would collect like terms by combining each term with the same exponent or raised to the same power. The term would be arranged in decreasing order of the exponents. It becomes

5x⁴ + 2x⁴ + 5x³ + 7x² + 4x + 2x - 9 + 14

7x⁴ + 5x³ + 7x² + 6x + 5

7 0
4 years ago
Find the distance between the points (3,0) and (-1,-5)
nadya68 [22]

Answer:

6.4

Step-by-step explanation:

distance formula \sqrt{(x2-x1)^2+(y2-y1)^2}

\sqrt{(-1-3)^2+(-5-0)^2}

\sqrt{(-4)^2+(-5)^2}

\sqrt{16+25}

\sqrt{41}≈6.403.......

ik it doesnt make any sinse but hope this helps

7 0
4 years ago
An architect has his floor plan for a house he is building. The foundation for the house has already been laid and measures 300
wlad13 [49]

Answer:

12

Step-by-step explanation:

You divide 300 by 25

300/25=12

His house is 12 in long on the floor plan

7 0
3 years ago
Simplify x+2/x^2+2x-3 divide by x+2/x^2-x
ira [324]

\dfrac{\frac{x+2}{x^2+2x-3}}{\frac{x+2}{x^2-x}}

If x\neq-2, then we can immediately cancel the factors of x+2:

\dfrac{\frac1{x^2+2x-3}}{\frac1{x^2-x}}=\dfrac{x^2-x}{x^2+2x-3}

Factorize the numerator and denominator:

x^2-x=x(x-1)

x^2+2x-3=(x+3)(x-1)

Next, if x\neq1, then

\dfrac{x^2-x}{x^2+2x-3}=\dfrac{x(x-1)}{(x+3)(x-1)}=\dfrac x{x+3}

8 0
3 years ago
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