The formula for the volume of a pyramid is,
V=1/3Bh
Since the base of the pyramid is a square, the base area is 11^2
which equals 121 sq. units
So, substitute 121
for B
and 6 for h, in the formula.
V=1/3(121)(6) = 242 cu. units
Or alternatively 1/3(11^2)(6) = 242 cu. units
Answer:
Radius=9
Diameter=18
Step-by-step explanation:
Step-by-step explanation:
I'll do the first problem as an example.
∠P and ∠H both have one mark. That means they're congruent.
∠T and ∠G both have two marks. So they're congruent.
∠W and ∠D both have three marks. So they're congruent.
So we can write a congruence statement:
ΔPTW ≅ ΔHGD
We can write more congruence statements by rearranging the letter, provided that corresponding pairs have the same position (P is in the same place as H, etc.). For example:
ΔWPT ≅ ΔDHG
ΔTWP ≅ ΔGDH