1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
julsineya [31]
2 years ago
6

10 miles = ________feet

Mathematics
2 answers:
lisov135 [29]2 years ago
7 0
10 miles=52800 feet (I know for sure)
Mnenie [13.5K]2 years ago
3 0
10 miles = 52800 feet :) <3
You might be interested in
Solve the system of equations for (x, y) using inverse matrices.
taurus [48]
Let’s see..................

5 0
3 years ago
A county environmental agency suspects that the fish in a particular polluted lake have elevated mercury levels. To confirm that
suter [353]

Answer:

a. The 95% confidence interval for the difference between means is (0.071, 0.389).

b. There is enough evidence to support the claim that the fish in this particular polluted lake have signficantly elevated mercury levels.

c. They agree. Both conclude that the levels of mercury are significnatly higher compared to a unpolluted lake.

In the case of the confidence interval, we reach this conclusion because the lower bound is greater than 0. This indicates that, with more than 95% confidence, we can tell that the difference in mercury levels is positive.

In the case of the hypothesis test, we conclude that because the P-value indicates there is a little chance we get that samples if there is no significant difference between the mercury levels. This indicates that the values of mercury in the polluted lake are significantly higher than the unpolluted lake.

Step-by-step explanation:

The table with the data is:

Sample 1 Sample 2

0.580    0.382

0.711      0.276

0.571     0.570

0.666    0.366

0.598

The mean and standard deviation for sample 1 are:

M=\dfrac{1}{5}\sum_{i=1}^{5}(0.58+0.711+0.571+0.666+0.598)\\\\\\ M=\dfrac{3.126}{5}=0.63

s=\sqrt{\dfrac{1}{(n-1)}\sum_{i=1}^{5}(x_i-M)^2}\\\\\\s=\sqrt{\dfrac{1}{4}\cdot [(0.58-(0.63))^2+...+(0.598-(0.63))^2]}\\\\\\            s=\sqrt{\dfrac{1}{4}\cdot [(0.002)+(0.007)+(0.003)+(0.002)+(0.001)]}\\\\\\            s=\sqrt{\dfrac{0.015}{4}}=\sqrt{0.0037}\\\\\\s=0.061

The mean and standard deviation for sample 2 are:

M=\dfrac{1}{4}\sum_{i=1}^{4}(0.382+0.276+0.57+0.366)\\\\\\ M=\dfrac{1.594}{4}=0.4

s=\sqrt{\dfrac{1}{(n-1)}\sum_{i=1}^{4}(x_i-M)^2}\\\\\\s=\sqrt{\dfrac{1}{3}\cdot [(0.382-(0.4))^2+(0.276-(0.4))^2+(0.57-(0.4))^2+(0.366-(0.4))^2]}\\\\\\            s=\sqrt{\dfrac{1}{3}\cdot [(0)+(0.015)+(0.029)+(0.001)]}\\\\\\            s=\sqrt{\dfrac{0.046}{3}}=\sqrt{0.015}\\\\\\s=0.123

<u>Confidence interval</u>

We have to calculate a 95% confidence interval for the difference between means.

The sample 1, of size n1=5 has a mean of 0.63 and a standard deviation of 0.061.

The sample 2, of size n2=4 has a mean of 0.4 and a standard deviation of 0.123.

The difference between sample means is Md=0.23.

M_d=M_1-M_2=0.63-0.4=0.23

The estimated standard error of the difference between means is computed using the formula:

s_{M_d}=\sqrt{\dfrac{\sigma_1^2}{n_1}+\dfrac{\sigma_2^2}{n_2}}=\sqrt{\dfrac{0.061^2}{5}+\dfrac{0.123^2}{4}}\\\\\\s_{M_d}=\sqrt{0.001+0.004}=\sqrt{0.005}=0.07

The critical t-value for a 95% confidence interval is t=2.365.

The margin of error (MOE) can be calculated as:

MOE=t\cdot s_{M_d}=2.365 \cdot 0.07=0.159

Then, the lower and upper bounds of the confidence interval are:

LL=M_d-t \cdot s_{M_d} = 0.23-0.159=0.071\\\\UL=M_d+t \cdot s_{M_d} = 0.23+0.159=0.389

The 95% confidence interval for the difference between means is (0.071, 0.389).

<u>Hypothesis test</u>

This is a hypothesis test for the difference between populations means.

The claim is that the fish in this particular polluted lake have signficantly elevated mercury levels.

Then, the null and alternative hypothesis are:

H_0: \mu_1-\mu_2=0\\\\H_a:\mu_1-\mu_2> 0

The significance level is 0.05.

The sample 1, of size n1=5 has a mean of 0.63 and a standard deviation of 0.061.

The sample 2, of size n2=4 has a mean of 0.4 and a standard deviation of 0.123.

The difference between sample means is Md=0.23.

M_d=M_1-M_2=0.63-0.4=0.23

The estimated standard error of the difference between means is computed using the formula:

s_{M_d}=\sqrt{\dfrac{\sigma_1^2}{n_1}+\dfrac{\sigma_2^2}{n_2}}=\sqrt{\dfrac{0.061^2}{5}+\dfrac{0.123^2}{4}}\\\\\\s_{M_d}=\sqrt{0.001+0.004}=\sqrt{0.005}=0.07

Then, we can calculate the t-statistic as:

t=\dfrac{M_d-(\mu_1-\mu_2)}{s_{M_d}}=\dfrac{0.23-0}{0.07}=\dfrac{0.23}{0.07}=3.42

The degrees of freedom for this test are:

df=n_1+n_2-1=5+4-2=7

This test is a right-tailed test, with 7 degrees of freedom and t=3.42, so the P-value for this test is calculated as (using a t-table):

\text{P-value}=P(t>3.42)=0.006

As the P-value (0.006) is smaller than the significance level (0.05), the effect is significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that the fish in this particular polluted lake have signficantly elevated mercury levels.

<u> </u>

c. They agree. Both conclude that the levels of mercury are significnatly higher compared to a unpolluted lake.

In the case of the confidence interval, we reach this conclusion because the lower bound is greater than 0. This indicates that, with more than 95% confidence, we can tell that the difference in mercury levels is positive.

In the case of the hypothesis test, we conclude that because the P-value indicates there is a little chance we get that samples if there is no significant difference between the mercury levels. This indicates that the values of mercury in the polluted lake are significantly higher than the unpolluted lake.

7 0
3 years ago
Solve 4x−9y=13 for y.
Irina18 [472]

Answer:

y =  -  \frac{13}{9}  +  \frac{4}{9} x

Step-by-step explanation:

4x - 9y = 13

4x - 9y - 4x = 13 - 4x

- 9y = 13 - 4x

y = 9y \div (9) = (13 - 4x) \div ( - 9)

y = (13 - 4x) \div( - 9)

y = 13 \div ( - 9) - 4x \div ( - 9)

y =  - 13 \div 9 - 4x \div ( - 9)

y =  -  \frac{13}{9}  - 4x \div ( - 9)

y =  -  \frac{13}{9}  + 4x \div 9

\boxed{\green{y =  -  \frac{13}{9}  +  \frac{4}{9} x, x E R}}

8 0
3 years ago
Which answer gives the correct inequality for the following number line?
rodikova [14]

Answer:

  • n < -2

Step-by-step explanation:

Numbers to the left from -2

<u>Set of numbers:</u>

  • (- oo, -2)

<u>The inequality for the given line:</u>

  • n < -2

<u />

4 0
3 years ago
3. WEDNESDAY (5/20): The minimum of the graph of a quadratic function is located at (-1,2). The point (2, 2015
Vadim26 [7]

Answer:

C.) f(x) = 2x^2 + 4x + 4

Step-by-step explanation:

The equation of the parabola with vertex (h,k) is y=a(−h+x)^2+k.

Thus, the equation of the parabola is y=a(x+1)^2+2.

To find a, use the fact that the parabola passes through the point (2,20): 20=9a+2.

Solving this equation, we get that a=2.

Thus, the equation of the parabola is y=2(x+1)^2+2.

TO STANDARD FORM

= 2*(x^2+2x+1)+2  

=(2x^2+4x+2)+2  

= 2x^2+4x+2+2  

= 2x^2+4x+4

8 0
3 years ago
Other questions:
  • Which of the following is a solution to the equation x - 5/7 = -3/7
    8·1 answer
  • What number is 15% of 63
    6·2 answers
  • Plzzzzz help with this asap
    14·1 answer
  • 8. How many ways can a committee of 5 students be chosen from a student council of 30 students? Is the order in which the member
    7·1 answer
  • longitud del radio de la circunferencia circunscrita a un heptágono regular si su diagonal de menor longitud mide 42 cm
    15·1 answer
  • An angle whose measure is _302° is in standard position. In which quadrant does the terminal side of the angle fall?
    13·2 answers
  • Solve for b2 in A = 1/2 h ( b1 + b2 ), if A = 16, h = 4, and b1 = 3.
    10·1 answer
  • Step 1: A poll of 1500 college students were asked whether or not they had used the Internet to find a place to live sometime wi
    9·1 answer
  • Omg i am bored so answer and get points will mark as brelenzz
    11·1 answer
  • How do you solve this?
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!