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Xelga [282]
3 years ago
10

a 5kg block on a rough horizontal surface is attached to a light spring (force constant=1.6kN/m). the block passes through its e

quilibrium position with a kinetic energy of 5J and is brought momentarily to rest after stretching the spring .06m. how much work is done by the frictional force on the block as it moves from its equilibrium position to the point of momentary rest?
Physics
1 answer:
natima [27]3 years ago
5 0

Answer:

2.12 J

Explanation:

Initial kinetic energy = final elastic energy + work by friction

KE = EE + W

KE = ½ kx² + W

5 J = ½ (1600 N/m) (0.06 m)² + W

W = 2.12 J

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Power is the rate work is usually done in.
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Rzqust [24]

Answer:

There will be 1800 W power consumption in heater

Explanation:

We have given current flowing in the heater I = 15 A

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We know that power consumption is given by P = VI

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So there will be 1800 W power consumption in heater

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3 years ago
Please answer the question below
scoundrel [369]
The correct answer is B.
In a velocity vs time graph, a line going up means an increase in velocity, or speed, which correlates to positive acceleration. Negative acceleration means slowing down.
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3 years ago
A family took a trip in a car traveling East from Greensboro to Wilmington, NC. Use the Graph to answer the questions below.
kotykmax [81]

Answer:

1). Average speed = 1.5 m per second

2). Average velocity = 1.5 m per second

Explanation:

1). Since, speed is a scalar quantity

   Therefore, average speed of the trip = \frac{\text{Total distance covered}}{\text{Total time taken}}

    From the graph attached,

   Total distance covered = 10 + 10 + 20 + 0 + 20 + 30

                                           = 90 meters

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    Average speed = \frac{90}{60}

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2). Velocity is a vector quantity.

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                                                   = \frac{90-0}{60-0}

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7 0
3 years ago
A spherical balloon has a radius of 6.55 m and is filled with helium. The density of helium is 0.179 kg/m3, and the density of a
Ksju [112]

Answer:

M_1 = 317.7 kg

Explanation:

Mass of the helium gas filled inside the volume of balloon is given as

m = \rho V

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m = 0.179(\frac{4}{3}\pi 6.55^3)

m = 210.7 kg

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1200.7 + M_1 = 1518.4

M_1 = 317.7 kg

3 0
3 years ago
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