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kondaur [170]
3 years ago
9

An electromagnetic wave travels in a vacuum. The wavelength of the wave is tripled. How is this accomplished?

Physics
1 answer:
love history [14]3 years ago
5 0

Answer:

The wavelength of the wave is tripled this can be done by reducing the frequency of the wave by factor of three.

Explanation :

The relation between the wavelength & frequency of a wave is given by

C = ν λ

Where

C - it is the velocity of light in vacuum.

ν - frequency of the wave.

λ - wavelength of the wave.

So we find that wavelength of a wave varies inversely with the frequency of a wave i.e. ν ∝ 1/λ.

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Alexxx [7]
Does electrical curents flows of charges across the membrane and the depolarization continues also due to charges that reject each other and the flow continues .so there appears a magnetic field as well
6 0
3 years ago
A potato is launched from the ground at an 73 degree angle with a velocity of 48 m/s.
Wittaler [7]

Answer:

107.4 meters

Explanation:

gravity is 9.8m/s^2

max height = (velocity squared times sin squared angle) ÷ ( speed of gravity times 2 )

max height = (48 squared times sin of 73 squared) ÷ ( 9.8 times 2 )

8 0
2 years ago
A vector has a magnitude of 30m at an angle of 225 degrees with respect to the positive x-axis and has a magnitude of 13m.what a
Aneli [31]

Answer:

I'm pretty sure this is not a complete question. My guess is that you are trying to add/subtract vectors. Vectors have both magnitude and direction, so vector A is pretty clear, but a magnitude of 13 (i'm guessing a resultant) without a direction is weird.

IF 13 is the magnitude of the resultant, vector B added to vector A could have any magnitude 17 ≤ B ≤ 43

It could have any direction of

θ = (225 - 180) ± arcsin(13/30)

θ = 45 ± 25.679...

70.679 ≤ θ ≤ 19.321

components of vector B would be

Bx = |B|cosθ

By = |B|sinθ

3 0
2 years ago
What is the magnification of an astronomical telescope whose objective lens has a focal length of 74 cm and whose eyepiece has a
Novay_Z [31]

Answer:

The magnification of an astronomical telescope is -30.83.

Explanation:

The expression for the magnification of an astronomical telescope is as follows;

M=-\frac{f_o}{f_e}

Here, M is the magnification of an astronomical telescope, f_e is the focal length of the eyepiece lens and f_o is the focal length of the objective lens.

It is given in the problem that an astronomical telescope having a focal length of objective lens 74 cm and whose eyepiece has a focal length of 2.4 cm.

Put f_o=74 cm and f_e=2.4 cm in the above expression.

M=-\frac{74}{2.4}

M=-30.83

Therefore, the magnification of an astronomical telescope is -30.83.

5 0
3 years ago
At which part of its orbit is the planet traveling at the slowest speed?<br> A, B, C, or D
Natali [406]
I think its D im not sure tho
3 0
3 years ago
Read 2 more answers
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