A very large amount of energy is produced from a very small mass. hoped this helped!!!
Answer:u=-22 m/s
Explanation:
Given
mass of puck 
Average force 
time of contact 
puck leaves with a velocity of 
We know impulse is 

therefore



Final momentum 


Impulse on the ball 
Impulse
Initial velocity is given by

i.e. initially ball is moving towards -x-axis
The
half-life of this radioactive isotope is 9 months for it decreases to
one-fourth its original amount in 18 months. Half-life means a certain length
of time after which half of the amount of radioactive element has decayed.
Therefore,
the half-life of this particular isotope is 18 months. After 18 months the
isotope was at one-half, then another 18 months, the isotope was at one-fourth,
which is 9 months where one-fourth is one-half of one half.
Solution:
f ( t )= 20 S ( t ) + 55/30 tS ( t )− 55/30 ( t − 30 ) S ( t − 30 )
• Taking the Laplace Transform:
F ( s ) = 20/s + 55/30 ( 1/s^2 ) – 55/30 ( 1/s^2) e^-30s = 20/s + 55/30 ( 1/s^2 ) ( 1 – e^-30s)