Although the video is not found here, the sentence makes reference to the transmission spectrum of colored filters.
<h3>What is the transmission spectrum?</h3>
The transmission spectrum indicates the light portion having a given wavelength that can be passed through a filter.
This spectrum (transmission spectrum) depends on the physical separation of the particles that form the filter.
In conclusion, although the video is not found here, the sentence makes reference to the transmission spectrum of colored filters.
Learn more about the transmission spectrum here:
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Voltage = current * resistance
V = I*R
I = 4 A
R = 2 ohm
V = 4 A * 2 ohm
= 8 volt
Answer:
★The second law of refraction
The ratio of sine of angle of incidence to the sine of angle of refraction is a constant for a light of given colour and for a given pair of media. This law is also called Snell's law of refraction. If 'i' is the angle of incidence and 'r' is the angle of refraction then, Sin i/Sin r = constant
This constant value is called the refractive index of the second medium with respect to the first.
Answer:
v = ((m + M) / m)*√(2*g*h)
Explanation:
Given
m = mass of the projectile
M = mass of the ballistic pendulum
v = initial speed of the projectile
v' = speedof the system (pendulum + projectile) after the inelastic collision
h = maximum height reached for the system
Knowing that is an inelastic collision we have
m*v + M*(0) = (m+M)*v'
⇒ v' = m*v / (m+M)
After the collision, we apply the Principle of the Conservation of Energy
Ki + Ui = Kf + Uf
where
Ui = Kf = 0 J
then
Ki = Uf
0.5*(m+M)*v'² = (m+M)*g*h
⇒ 0.5*v'² = g*h
⇒ v'² = 2*g*h
⇒ (m*v / (m+M))² = 2*g*h
⇒ v = ((m+M) / m)*√(2*g*h)
Answer:
14,300 lines per cm
Explanation:
Answer:
14,300 cm per line
Explanation:
λ400 nm to 400nm
We can find the maximum number of lines per centimeter, which is reciprocal of the least distance separating two adjacent slits, using the following equation.
mλ = dsin (θ)
In this equation,
m is the order of diffraction.
λ is the wavelength of the incident light.
d is the distance separating the centers of the two slits.
θ is the angle at which the mth order would diffract.
To find the least separation that allows the observation of one complete order of spectrum of the visible region, we use the maximum wavelength of the visible region is 700 nm.
d = mλ / sin (θ)
As we want the distance d to be the smallest then sin (θ) must be the greatest, and the greatest value of the sin (θ) is 1. For that we also use the longest wavelength because using the smallest wavelength, the longest wavelength would not be diffracted.
d = mλ / sin (θ)
d = 1 x 700nm / 1
= 700 nm
So, the least separation that would allow for the possibility of observing complete first order of the visible region spectra is 700 nm, and knowing the least separation we can find the maximum number of lines per cm, which is the reciprocal of the number of lines per cm.
n = 1/d
= 1 / 700 x 
= 1, 430,000 lines per m
= 14,300 lines per cm
<u>The maximum number of lines per cm, that would allow for the observation of the complete first order visible spectra.</u>
