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posledela
3 years ago
15

Please help. It’s probably easy

Physics
1 answer:
iragen [17]3 years ago
7 0
I believe it’s 60km/h

I divided the total distance (120 km) by the time it took to get there (2h) to get this.
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When a force of 15 newtons is applied to a stationary chair, it starts moving. What can you say about the frictional force betwe
harkovskaia [24]
First you need to make a difference between friction while object is stationary and the friction while object is moving. Force required to start moving some object is slightly greater than force required to maintain objects movement. That means that to move a chair you need some force F1 but you can than slightly reduce force and chair will still be moving.

Now to the problem in this question: It can be said that "stationary friction force" is equal to 15 Newtons. Its also good to know that friction force between chair and floor while you are increasing your push is also increasing and is equal to force of your push. Once it reaches 15N which is it "critical value" for that chair, chair starts moving and friction force drops a little bit and now it is called friction force of moving chair.
3 0
3 years ago
PLEASE HELP RIGHT ANSWER WILL GET THE BRAINLY..
Basile [38]

Answer:

erosion

Explanation:

it carries things from one place to another

3 0
3 years ago
Read 2 more answers
A constant force of 120 N pushes a 55 kg wagon across an 8 m level surface. If the wagon was initially at rest, what is the fina
Illusion [34]

Answer:

The kinetic energy of the wagon is 967.0 J

Explanation:

Given that,

Force = 120 N

Mass = 55 kg

Height = 8 m

We need to calculate the kinetic energy of the wagon

Using newtons law

F = ma

\dfrac{120}{55}=a

a =2.2\ m/s^2

Using equation of motion

v^2 =u^2+2as

Where,

v = final velocity

u = initial velocity

s = height

Put the value in the equation

v^2=0+2\times2.2\times8

v=5.93\ m/s

Now, The kinetic energy is

K.E=\dfrac{1}{2}mv^2

K.E=\dfrac{1}{2}\times55\times(5.93)^2

K.E=967.0\ J

Hence, The kinetic energy of the wagon is 967.0 J

3 0
3 years ago
A bird watcher meanders through the woods, walking 1.93 km due east, 1.03 km due south, and 3.84 km in a direction 52.8 ° north
Sedaia [141]

Answer:

Magnitude of displacement = 2.07 km

Magnitude of average velocity = 1.17 kmph

Explanation:

Let east represent positive x axis and north represent positive y axis.

A bird watcher meanders through the woods, walking 1.93 km due east, 1.03 km due south, and 3.84 km in a direction 52.8 ° north of west.

1.93 km due wast

           s ₁ = 1.93 i km

1.03 km due south

           s₂ = -1.03 j km

3.84 km in a direction 52.8 ° north of west

           s₃ = -3.84 cos 52.8 i + 3.84 sin 52.8 j = -2.32 i + 3.06 j km

Total displacement

          s = s ₁+  s₂+ s₃ = 1.93 i - 1.03 j -2.32 i + 3.06 j = -0.39 i + 2.03 j

  Magnitude of displacement, =\sqrt{(-0.39)^2+2.03^2}=2.07km

Time taken = 1.771 hour

Magnitude of average velocity, =\frac{2.07}{1.771}=1.17km/hr

7 0
3 years ago
How much time does it take a person to walk 12 km north at a velocity of 6.5 km/hr
Stella [2.4K]
1.8461 km/hr Well i need more characters so i might as well type a beautiful sentence for you to read and waste your time on.
3 0
3 years ago
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