Complete the ratio table to convert the units of time from hours to weeks to hours.

Mathematics

1 answer:

-Dominant- [34]2 years ago

5 0

Answer:

I am very sry I dont know the answer but I need points

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What are the solutions for x when y is equal to 0 in the quadratic function y=x^2-8x

Elena L [17]

I would use the quadratic formula for this:

x = -b ± √b² - 4ac over 2a
x = 8 ± √64 - 4(1)(0) over 2(1)
x = 8 ± √64 over 2
x = 8 <span>± 8 over 2 [simplify]
x = 4 </span><span>± 4
x1 = 4 + 4 x2 = 4 - 4
x1 = 8 x2 = 0

Thus, the solutions for x would be 0 and 8.</span>

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2 years ago

The dealer's cost of a Sierra is 89% of a base price. Which is $43,890, and 10 points

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It’s 450 i’m pretty sure

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The midpoint of AB is M(1,−3). If the coordinates of A are (-6, -7) what are the coordinates of B?

abruzzese [7]

Answer:5464

Step-by-step explanation:

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2 years ago

A huge ice glacier in the Himalayas initially covered an area of 454545 square kilometers. Because of changing weather patterns,

zloy xaker [14]

Answer:

$t=-20ln\left(\dfrac{1}{3}\right)$

Step-by-step explanation:

The relationship between A, the area of the glacier in square kilometers, and t, the number of years the glacier has been melting, is modeled by the equation.:

$A=45e^{-0.05t}$

We want to determine the value of t for which the area, A(t)=15 square kilometers.

$15=45e^{-0.05t}\\$Divide both sides by 45\\\dfrac{15}{45} =\dfrac{45e^{-0.05t}}{45}\\\dfrac{1}{3}=e^{-0.05t}\\$Take the natural logarithm of both sides\\ln\left(\dfrac{1}{3}\right)=ln\left(e^{-0.05t}\right)\\ln\left(\dfrac{1}{3}\right)=-0.05t\\$Divide both sides by -0.05$\\t=-\dfrac{ln\left(\dfrac{1}{3}\right)}{0.05} \\=-\dfrac{ln\left(\dfrac{1}{3}\right)}{0.05}\\t=-20ln\left(\dfrac{1}{3}\right)$

Therefore, the time for which the area will be 15 sqyare kilometers is:

-20 ln(1/3) years.

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2 years ago

BRAINLY I NEED HELP ASAPPPP!!

Karo-lina-s [1.5K]

Answer:

Step-by-step explanation:

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2 years ago