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-BARSIC- [3]
3 years ago
15

The two pond system is fed by a stream with flow rate 1.0 MGD (million gallons per day) and BOD (nonconservative pollutant) conc

entration of 20 mg/L. The rate of decay of BOD is 0.3/day. The volume of the first pond is 5 million gallons and the second is 3 million. Assuming complete mixing within the pond, find the BOD concentration leaving each pond.
Engineering
1 answer:
svlad2 [7]3 years ago
3 0

Answer: First pond= 8.0 mg/L

second pond = 4.2 mg/L

Explanation:

Cn/Co = [ 1/ [ 1 + (k*t/n)]]

for the first pond

where Co into the first pond is 20mg/L,

Cn = 20*[ 1/ [ 1+ ((1 x 5)/0.3)]]

Cn = 8 mg/L

into the second pond we calculate the BOD leaving the pond of volume 3million liters

we have Cn = 4.2 mg/L

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What happens if your son makes a spark in a outlet and then the room goes dark
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Answer:

He probably tripped the wiring, when metal hits the electricity it creates a reaction that burns the wiring.

Explanation:

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3 years ago
In your new role at Wayne Industries, you have been given the freedom to propose and develop your own project ideas. You have an
gulaghasi [49]

Answer:

461.65 KJ/Kg

Explanation:

In this question, we are asked to calculate the values of heat transferred in the process.

Please check attachment for complete solution and step by step explanation

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4 years ago
A piston moves a 25kg hammerhead vertically down 1m from rest to a
UkoKoshka [18]

Answer:

Total change in energy = 31 KJ.

Explanation:

Mass m=25 kg

Height h = 1 m

Initial velocity = 0

Final velocity = 50 m/s

Energy at initial condition

E_1=mgh+\dfrac{1}{2}mv^2

E_1=25\times 10\times 1+0

E_1=250\ J

Energy at final condition

E_2=0+\dfrac{1}{2}\times 25\times 50^2

E_2=31250\ J

So the change in energy = 31250 -250 J

The total change in energy = 31000 J

5 0
4 years ago
Read 2 more answers
Draw a 3-D physical structure of an NMOS transistor. Label four terminals: body, drain, gate, and source. And also label silicon
Vanyuwa [196]

Answer:

Answer is attached.

Explanation:

A NMOS is a n-channel MOSFET or Metal Oxide

Semiconductor Field Effect Transistor. This type

of transistor might be an enhancement or

depletion type nMOS transistor designed using

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4 0
3 years ago
Compute the repeat unit molecular weight of PTFE. Also compute the number-average molecular weight for a PTFE for which the degr
MatroZZZ [7]

Answer:

a) the repeat unit molecular weight of PTFE MW = 100.015 g/mole

b) the number-average molecular weight for a PTFE for which the degree of polymerization is 10,000 щₙ = 1000150 g/mole

Explanation:

Given that;

PTFE which is also called Polytetrafluoroethylene

structure  of repeat unit of Polytetrafluoroethylene

(C2F4)n

a)

To compute the repeat unit molecular weight

we say

MW = 2( atomic weight of C ) + 4( atomic weight of F)

MW = 2 (12.0107) + 4 ( 18.9984)

MW = 100.015 g/mole

therefore the repeat unit molecular weight of PTFE MW = 100.015 g/mole

b)

To compute the number-average molecular weight for  PTFE of which the degree of polymerization is 10,000

we say

DP = щₙ / MW

where щₙ is the number of average molecular weight,

MW is the repeat unit molecular weight give as 100.015 g/mole

DP is degree of polymerization which is 10,000

Now we substitute

10,000 = щₙ / 100.015

щₙ = 10,000 × 100.015

щₙ = 1000150 g/mole

Therefore the number-average molecular weight for a PTFE for which the degree of polymerization is 10,000 щₙ = 1000150 g/mole

3 0
3 years ago
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