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seropon [69]
3 years ago
14

What are three automotive safety systems

Engineering
1 answer:
abruzzese [7]3 years ago
7 0

Answer:

Head-Up Display, Anti-Lock Braking Systems, and Electronic Stability Control.

Explanation:

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You are watching the weather forecast and the weatherman says that strong thunderstorms and possible tornadoes are likely to for
WITCHER [35]

Explanation:

bad weather usually form when low pressure pushed high pressure ot the way.

5 0
3 years ago
Write SQL queries to answer the following questions: What are the names of the course(s) that student Altvater took during the s
amm1812

Answer:

See explanations

Explanation:

Consider the following Venn diagram to retrieve the name of course that student Altvater took during semester I-2015.

• In above Venn diagram inner Ellipse represent the subquery part, this subquery part select the Student ID from STUDENT table.

• Second sub query is used to determine the SectionNo of all student whose studentID retrived in the first subquery

• Finally the main query displays the CourseName from COURSE table.

6 0
4 years ago
Water flows through a converging pipe at a mass flow rate of 25 kg/s. If the inside diameter of the pipes sections are 7.0 cm an
ser-zykov [4K]

Answer:

volumetric flow rate = 0.0251 m^3/s

Velocity in pipe section 1 = 6.513m/s

velocity in pipe section 2 = 12.79 m/s

Explanation:

We can obtain the volume flow rate from the mass flow rate by utilizing the fact that the fluid has the same density when measuring the mass flow rate and the volumetric flow rates.

The density of water is = 997 kg/m³

density = mass/ volume

since we are given the mass, therefore, the  volume will be mass/density

25/997 = 0.0251 m^3/s

volumetric flow rate = 0.0251 m^3/s

Average velocity calculations:

<em>Pipe section A:</em>

cross-sectional area =

\pi \times d^2\\=\pi \times 0.07^2 = 3.85\times10^{-3}m^2

mass flow rate = density X cross-sectional area X velocity

velocity = mass flow rate /(density X cross-sectional area)

velocity = 25/(997 \times 3.85\times10^{-3}) = 6.513m/s

<em>Pipe section B:</em>

cross-sectional area =

\pi \times d^2\\=\pi \times 0.05^2= 1.96\times10^{-3}m^2

mass flow rate = density X cross-sectional area X velocity

velocity = mass flow rate /(density X cross-sectional area)

velocity = 25/(997 \times 1.96\times10^{-3}) = 12.79m/s

7 0
3 years ago
Manufacturing employees who perform assembly line work are referred to as
mamaluj [8]

Answer:

C. assembly line workers.

Explanation:

8 0
3 years ago
Read 2 more answers
I need help with this I dont know the word ​
DiKsa [7]

Would it be Unit?

...............

5 0
3 years ago
Read 2 more answers
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