Incomplete question as the charge density is missing so I assume charge density of 3.90×10^−12 C/m².The complete one is here.
An electron is released from rest at a distance of 0 m from a large insulating sheet of charge that has uniform surface charge density 3.90×10^−12 C/m² . How much work is done on the electron by the electric field of the sheet as the electron moves from its initial position to a point 3.00×10−2 m from the sheet?
Answer:
Work=1.06×10⁻²¹J
Explanation:
Given Data
Permittivity of free space ε₀=8.85×10⁻¹²c²/N.m²
Charge density σ=3.90×10⁻¹² C/m²
The electron moves a distance d=3.00×10⁻²m
Electron charge e=-1.6×10⁻¹⁹C
To find
Work done
Solution
The electric field due is sheet is given as
E=σ/2ε₀
Now we need to find force on electron
Now for Work done on the electron
Answer:
The mercury in the barometer rises by a height of 0.0764 m = 76.4 cm = 764 mm
Explanation:
The change in pressure is related to the density of fluid and height risen by the fluid through the relation
ΔP = ρgh
ΔP = change in pressure = P₂ - P₁ = 1.1 - 1.0 = 0.1 atm = 0.1 × 101325 Pa = 10132.5 Pa
ρ = density of the fluid = 13,534 kg/m³
g = acceleration due to gravity = 9.8 m/s²
h = height through which the mercury in barometer rises = ?
10132.5 = 13534 × 9.8 × h
h = (10132.5) ÷ (13534 × 9.8)
h = 0.0763948996 = 0.0764 m = 76.4 cm = 764 mm
Hope this Helps!!!
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While the boy is sitting on the chair it creates a force downward on the chair and therefore the chair takes it and gives off the equal amount of force. So while he is putting force downward the chair is putting the same force upward.
Answer:
0.28m/s²
Explanation:
Force = mass•acceleration
F = m•a
50 = 176•a Divide both sides by 176:
50/176 = a ≈ 0.28 m/s²
