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3 years ago

15

When a marble rolls from starting point to a stopping point the type of motion is called ____ _.

1 answer:

Yuliya22 [10]3 years ago

8 0

Answer: <em>Rotational motion</em>

Explanation: The two types of motion of the rolling ball are translational motion and rotational motion. The center of mass of the ball undergoes translational motion whereas the ball undergoes rotational motion in the center of mass frame.

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A transverse wave has a wavelength of 0.50 m and a frequency of 20 hz. what is the wave speed?

Alona [7]

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3 years ago

A spinning disc rotating at 130 rev/min slows and stops 31 s later. how many revolutions did the disc make during this time?

gayaneshka [121]

F = 130 revs/min = 130/60 revs/s = 13/6 revs/s
t = 31s
wi = 2πf = 2π × 13/6 = 13π/3 rads/s
wf = 0 rads/s = wi + at
a = -wi/t = -13π/3 × 1/31 = -13π/93 rads/s²
wf² - wi² = 2a∅
-169π²/9 rads²/s² = 2 × -13π/93 rads/s² × ∅
∅ = 1209π/18 rads
n = ∅/2π = (1209π/18)/(2π) = 1209/36 ≈ 33.5833 revolutions.

3 0

3 years ago

A basketball has a mass of 1 kg and is traveling 12 m/s

cricket20 [7]

A) It would be doubled.

Why?

To answer the question, we just need to calculate the momentum of the basketball using the following formula:

$Momentum=mass*velocity\\\\Momenum=1kg*12\frac{m}{s}=12\frac{kg.m}{s}$

Now, we have calculated the momentum and the result is 12 kg.m/s, what would happen to the velocity if we double the momentum? Let's calculate it!

$Momentum=mass*velocity\\\\(2)*12\frac{kg.m}{s}=1kg*velocity\\\\velocity=\frac{24\frac{kg.m}{s} }{1kg} =24\frac{s}{s}$

Hence, we can see that if the momentum is doubled, the velocity will be doubled too.

Have a nice day!

7 0

3 years ago

A frictionless piston–cylinder device contains 5 kg of nitrogen at 100 kPa and 250 K. Nitrogen is now compressed slowly accordin

Arte-miy333 [17]

Answer:

The work input during this process is -742 kJ

Explanation:

Given;

Initial temperature of nitrogen T₁ = 250 K

final temperature of nitrogen T₂ = 450 K

mass of nitrogen, m = 5 kg

$PV^{1.4} = constant$

The work input during the process is calculated as;

$W = \frac{m*R(T_2-T_1)}{1-n}$

where;

R is gas constant = 0.2968 kJ/kgK

substitute given values in above equation.

$W = \frac{m*R(T_2-T_1)}{1-n} = \frac{5*0.2968(450-250)}{1-1.4} = -742 \ kJ$

Therefore, the work input during this process is -742 kJ

8 0

4 years ago

The temperature of a plastic cube is monitored while the cube is pushed 3.4 m across a floor at constant speed by a horizontal f

Nesterboy [21]

Answer:

$\Delta E_{floor} = 51 J$

Explanation:

The work (W) done on the cube to be pushed across the floor is equal to the total thermal energy (ΔE) of the system:

$W = \Delta E_{T} = \Delta E_{cube} + \Delta E_{floor}$ (1)

Also, the work done on the cube by the horizontal force is giving by:

$W = F \cdot d$ (2)

<em>where F: force applied to the cube , d: displacement of the cube </em>

<em>By equaling the equations (1) and (2)</em>, we can find the thermal energy of the floor:

$\Delta E_{cube} + \Delta E_{floor} = F \cdot d$

$\Delta E_{floor} = F \cdot d - \Delta E_{cube}$

$\Delta E_{floor} = 20 N \cdot 3.4 m - 17 J$

$\Delta E_{floor} = 51 J$

So, the increase in the thermal energy of the floor is 51 J.

Have a nice day!

7 0

3 years ago