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konstantin123 [22]
3 years ago
15

In what cardio-vascular sports do you consider the importance of motion? Why?​

Physics
1 answer:
maria [59]3 years ago
3 0
Cardiovascular (aerobic) exercise: increases your energy and stamina • helps control blood pressure • improves your blood lipid profile (cholesterol) • helps you burn extra calories to maintain an ideal weight.
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A race car starts from rest and travels east along a straight and level track. For the first 5.0 ss of the car's motion, the eas
irina [24]

Answer:

The acceleration of the car is 7.85 m/s²

Explanation:

Given;

vx(t)= (0.910m/s³)t², given time traveled by the car 't' = 5.0 s

⇒To determine the velocity for 5 seconds, we substitute in 5.0 s for t

vx(5)= (0.910m/s³)(5s)²

       = (0.910m/s³)(25s²)

      vx = 22.75 m/s

⇒To determine the acceleration of the car when vx=12.0m/s

Acceleration is change in velocity per unit time

when vx=12.0m/s, our new equation becomes; 12 = (0.910m/s³)t²

Solving for t: t² = 12/0.91

                     t² = 13.187

                      t = √13.187 = 3.63 s

  Acceleration = Δv/Δt

                        = \frac{(22.75 - 12)m/s}{(5-3.63)s} = (\frac{10.75}{1.37}).\frac{m}{s^2}

  Acceleration = 7.85 m/s²

3 0
4 years ago
How much physical activity do children and trens need?
saveliy_v [14]

Answer:

it should be 60 min at least 3 days a week

8 0
3 years ago
Suppose high tide is at midnight, the water level at midnight is 3 m, and the water level at low tide is 0.5 m. Assuming the nex
aev [14]

We have that the time, to the nearest minute, when the water level is at 1.125 m for the second time after midnight is

t=10.0hours

From the Question we are told that

Maximum height h_{max}=3m

Minimum height  H_{min}=0.5m

Time for  next high tide will occurT=12 hours =>720 min

Generally Average Height

h_{avg}=\frac{3+0.5}{2}\\\\h_{avg}=1.75

Therefore determine Amplitude to be

A=h_{max}=j_{avg}\\\\A=3-1.75\\\\A=1.25

Generally, the equation for Time is mathematically given by

At t=0

h(x)=Acos(Bx)+h_{avg}

Where

B=\frac{2\pi}{P}\\\\B=\frac{2\pi}{720}\\\\B=8.73*10^{-3}

Therefore

h(t)=Acos8.73*10^{-3}(t)+h_{avg}

Hence the Time at T=1.125 is

1.125(t)=1.25cos(8.73*10^{-3})(t)+1.75

-0.1249t=1.75

t=10.0hours

For more information on this visit

brainly.com/question/22361343

5 0
3 years ago
A lever has a mechanical advantage of 5.4. If you apply a force of 500 N to the lever, how much force does the lever apply to th
Yanka [14]

Force applied by the lever to the object=2700 N

Explanation:

Mechanical advantage= \frac{LOAD}{EFFORT}

mechanical advantage= 5.4

effort force= 500 N

we need the load force

5.4= load/500

load=2700 N

Thus the force applied by the lever to the object=2700 N

6 0
3 years ago
What average net force is required to stop a 3.5 kg bowling ball initially travelling at a speed of 1.5 m/s over a distance of 0
raketka [301]

First the aceleration:

Vf² = Vo² - 2ad

a = (Vf² - Vo²) / 2d

a = (0 m/s)² - (1,5 m/s)²) / 2 * 0,4 m

a = -2,25 m²/s² / 0,8 m

a = -2,81 m/s²

Now, for the net force, use 2nd law of Newton:

F = ma

F = 3,5 kg * (-2,81 m/s²)

F = -9,835 N

The force for stop the bowling ball is <u>-9,835 Newtons.</u>

7 0
3 years ago
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