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Anton [14]
3 years ago
14

All of the following help to reduce the problem of social traps except ___________. Please select the best answer from the choic

es provided modelilng altruistic behaviors educating individuals about the effects of social traps establishing laws that decrease cooperative behavior establishing regulations on behaviors that have collective effects
IT WAS C
Physics
2 answers:
Olin [163]3 years ago
6 0

Answer:

<h2>Establishing laws that decrease cooperative behaviour.</h2>

Explanation:

A social trap refers to short term benefits, but long terms loss in a certain social group, that's why is called trap. One good example of social trap could be overexploitation of resources. Our societies is inside this social trap, which help to develop the economy, but with a long term ecology costs, because it degrades complete ecosystems.

So, in this case, the only answer that don't contribute to reduce this social problem, it's <em>"establishing laws that decrease cooperative behaviour", </em>because the lack of cooperativeness is one way to ensure the perpetuation and development of social traps.

All other options, actually contributes to reduce this social phenomenon. Modelling altruistic behaviours, education, and regulations on behaviour which could impact collectives, all of these are positive decisions that improve our social intelligence, and could ensure the reduce of social traps.

allsm [11]3 years ago
5 0
It’s c beside me in the
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Question 9 In an RC series circuit, ε = 12.0 V, R = 1.07 MΩ, and C = 2.66 µF. (a) Calculate the time constant. (b) Find the maxi
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Answer:

a.) τ = 2.85 s b.) Q = 3.19 * 10^-5 C c.) t = 1.691 s

Explanation:

So we are told that it is a RC circuit. We are told Q = C V [1 - e^(-t/RC)] = 12.0 V, R =  1.07 MΩ and C = 2.66 µF.

a.) The time constant for RC circuit, τ = RC. Substituting our known values we get:

τ = RC where R = (1.07 * 10 ^ 6)Ω and C = (2.66 * 10 ^ -6) F

τ = (1.07 * 10 ^ 6)Ω * (2.66 * 10 ^ -6) F = 2.8462 s ≈ 2.85 s

τ = 2.85 s

b.) The relationship between capacitance, potential, charge is given:

Q = CV[1-e^{-t/RC} ]

The capacitor is fully charge when t approaches infinity, therefore:

Q =  \lim_{t \to \infty} a_n CV[1-e^{-t/RC} ]

When t approaches infinity, the term e becomes very small (e^-∞ = 0), therefore we can simplify the equation and plug in our values

Q = (2.66*10^{-6}) F * (12.0)V *[1 - 0] = 3.192 * 10^{-5}

Q = 3.19 * 10^-5 C

c.) Using the same equation as before, we can substitute Q in and solve for Q:

(14.3 * 10 ^ 6) C = (2.66*10^{-6})F *(12.0)V*[1-e^{-t/(2.85s)}]\\0.552 = e^{-t/(2.85s)}\\t = -1 * 2.85 * ln(0.552) \\t = 1.69120678 s

t = 1.691 s

Hope this helps! I'm not sure what the units you want, so convert to the desired units.

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