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Studentka2010 [4]
2 years ago
7

Trong thí nghiệm về giao thoa sóng trên mặt nước gồm hai nguồn kết hợp S1S2 cách nhau 15 cm với dao động với tần số 30Hz. Tốc độ

truyền vòng 48 cm/s.
a. Tìm khoảng cách giữa hai cực đại gần nhau nhất.
b Tìm số điểm dao động với biên độ cực tiểu giữa S1S2.
c. Trong vùng giao thoa điểm M trên mái nhất cách S1S2 lần lược các khoảng MS1 =1,5 cm và MS2=7,9 cm. M là cực đại hay cực tiểu và là đường thứ bao nhiêu so với đường trung trực của S1S2.
Physics
1 answer:
mojhsa [17]2 years ago
6 0

Answer:

this is a difficult question but I will try to answer it answer for this is 3220 a + b b u s y d l new

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Answer:

\boxed{\sf Focal \ length = 10 \ cm}

Given:

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Explanation:

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\boxed{ \bold{\sf Focal \ length \ (f) = \frac{Radius \ of \ curvature \ (R)}{2}}}

Substituting value of R in the equation:

\sf \implies f =  \frac{20}{2}

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\sf \implies f = 10 \: cm

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