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Studentka2010 [4]
3 years ago
7

Trong thí nghiệm về giao thoa sóng trên mặt nước gồm hai nguồn kết hợp S1S2 cách nhau 15 cm với dao động với tần số 30Hz. Tốc độ

truyền vòng 48 cm/s.
a. Tìm khoảng cách giữa hai cực đại gần nhau nhất.
b Tìm số điểm dao động với biên độ cực tiểu giữa S1S2.
c. Trong vùng giao thoa điểm M trên mái nhất cách S1S2 lần lược các khoảng MS1 =1,5 cm và MS2=7,9 cm. M là cực đại hay cực tiểu và là đường thứ bao nhiêu so với đường trung trực của S1S2.
Physics
1 answer:
mojhsa [17]3 years ago
6 0

Answer:

this is a difficult question but I will try to answer it answer for this is 3220 a + b b u s y d l new

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What is the value of work done on an object when a 70–newton force moves it 9.0 meters in the same direction as the force?
slava [35]

Answer:

630 J

Explanation:

W = Fdcosθ

W = 70(9)cos0

W = 630 J

5 0
3 years ago
A dart hits a dartboard and stops in 0.060 s. The net force on the dart is 14 N during the collision.
Rainbow [258]

Answer:

<em>The change of momentum of the dart is 0.84 Nw.s</em>

Explanation:

<u>Impulse and change of momentum</u>

The change in momentum of an object is its mass times the change in its velocity:

\Delta p=m\Delta v=m(v_2-v_1)

The change in the momentum can also be found by considering the force acting on it. If a force F acts for a time Δt, the change of momentum is given by:

\Delta p=F.\Delta t

The dart hits a dashboard with a net force of 14 N during the collision and stops in 0.06 seconds. The change of momentum is:

\Delta p=14*0.06=0.84

The change of momentum of the dart is 0.84 Nw.s

5 0
3 years ago
A football player kicks a field goal from a distance of 45 m from the goalpost. The football is launched at a 35° angle above th
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7 0
2 years ago
A 1.1 kg ball is attached to a ceiling by a 2.16 m long string. The height of the room is 5.97 m . The acceleration of gravity i
nydimaria [60]

1. -23.2 J

The gravitational potential energy of the ball is given by

U=mgh

where

m = 1.1 kg is the mass of the ball

g = 9.8 m/s^2 is the acceleration of gravity

h is the height of the ball, relative to the reference point chosen

In this part of the problem, the reference point is the ceiling. So, the ball is located 2.16 m below the ceiling: therefore, the heigth is

h = -2.16 m

And the gravitational potential energy is

U=(1.1 kg)(9.8 m/s^2)(-2.16 m)=-23.2 J

2. 41.1 J

Again, the gravitational potential energy of the ball is given by

U=mgh

In this part of the problem, the reference point is the floor.

The height of the ball relative to the floor is equal to the height of the floor minus the length of the string:

h = 5.97 m - 2.16 m = 3.81 m

And so the gravitational potential energy of the ball relative to the floor is

U=(1.1 kg)(9.8 m/s^2)(3.81 m)=41.1 J

3. 0 J

As before, the gravitational potential energy of the ball is given by

U=mgh

Here the reference point is a point at the same elevation of the ball.

This means that the heigth of the ball relative to that point is zero:

h = 0 m

And so the gravitational potential energy is

U=(1.1 kg)(9.8 m/s^2)(0 m)=0 J

4 0
3 years ago
How do you change the currents in a circuit
mel-nik [20]
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Eddy Current Testing

Introduction
Basic Principles
History of ET
Present State of ET

The Physics
Properties of Electricity
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Circuits & Phase
Impedance
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Phase Lag

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Bridges
Impedance Plane
Display - Analog Meter

Probes (Coils)
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Probes - Configuration
Probes - Shielding
Coil Design
Impedance Matching

Procedures Issues 
Reference Standards
Signal Filtering

Applications
Surface Breaking Cracks
SBC using Sliding Probes
Tube Inspection 
Conductivity 
Heat Treat Verification
Thickness of Thin Mat'ls
Thickness of Coatings

Advanced Techniques
Scanning
Multi-Frequency Tech.
Swept Frequency Tech.
Pulsed ET Tech.
Background Pulsed ET
Remote Field Tech.

Quizzes

Formulae& Tables
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-






Current Flow and Ohm's Law

Ohm's law is the most important, basic law of electricity. It defines the relationship between the three fundamental electrical quantities: current, voltage, and resistance. When a voltage is applied to a circuit containing only resistive elements (i.e. no coils), current flows according to Ohm's Law, which is shown below.

I = V / R 

Where: 

I =

Electrical Current (Amperes)

V =

Voltage (Voltage)

R =

Resistance (Ohms)

    

Ohm's law states that the electrical current (I) flowing in an circuit is proportional to the voltage (V) and inversely proportional to the resistance (R). Therefore, if the voltage is increased, the current will increase provided the resistance of the circuit does not change. Similarly, increasing the resistance of the circuit will lower the current flow if the voltage is not changed. The formula can be reorganized so that the relationship can easily be seen for all of the three variables.

The Java applet below allows the user to vary each of these three parameters in Ohm's Law and see the effect on the other two parameters. Values may be input into the dialog boxes, or the resistance and voltage may also be varied by moving the arrows in the applet. Current and voltage are shown as they would be displayed on an oscilloscope with the X-axis being time and the Y-axis being the amplitude of the current or voltage. Ohm's Law is valid for both direct current (DC) and alternating current (AC). Note that in AC circuits consisting of purely resistive elements, the current and voltage are always in phase with each other.

Exercise: Use the interactive applet below to investigate the relationship of the variables in Ohm's law. Vary the voltage in the circuit by clicking and dragging the head of the arrow, which is marked with the V. The resistance in the circuit can be increased by dragging the arrow head under the variable resister, which is marked R. Please note that the vertical scale of the oscilloscope screen automatically adjusts to reflect the value of the current.

See what happens to the voltage and current as the resistance in the circuit is increased. What happens if there is not enough resistance in a circuit? If the resistance is increased, what must happen in order to maintain the same level of current flow?


4 0
3 years ago
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