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cricket20 [7]
3 years ago
11

1. When the mass of the ice added to the cup increases, the amount of thermal energy needed to change the temperature of the ice

decreases or increases
2. When the students measure the temperature of the water in the cups during the investigation, what is it the students are measuring?

Total kinetic energy of the water
Average kinetic energy of the water
Total amount of heat in the water

3. If the mass of ice added to the cup increases, the total energy in the cup will decrease or increase
Physics
1 answer:
Paha777 [63]3 years ago
3 0

1. When the mass of the ice added to the cup increases, the amount of thermal energy needed to change the temperature of the ice decreases or increases

2. When the students measure the temperature of the water in the cups during the investigation, what is it the students are measuring?

Total kinetic energy of the water

Average kinetic energy of the water

Total amount of heat in the water

3. If the mass of ice added to the cup increases, the total energy in the cup will decrease or increase1. When the mass of the ice added to the cup increases, the amount of thermal energy needed to change the temperature of the ice decreases or increases

2. When the students measure the temperature of the water in the cups during the investigation, what is it the students are measuring?

Total kinetic energy of the water

Average kinetic energy of the water

Total amount of heat in the water

3. If the mass of ice added to the cup increases, the total energy in the cup will decrease or increase1. When the mass of the ice added to the cup increases, the amount of thermal energy needed to change the temperature of the ice decreases or increases

2. When the students measure the temperature of the water in the cups during the investigation, what is it the students are measuring?

Total kinetic energy of the water

Average kinetic energy of the water

Total amount of heat in the water

3. If the mass of ice added to the cup increases, the total energy in the cup will decrease or increase1. When the mass of the ice added to the cup increases, the amount of thermal energy needed to change the temperature of the ice decreases or increases

2. When the students measure the temperature of the water in the cups during the investigation, what is it the students are measuring?

Total kinetic energy of the water

Average kinetic energy of the water

Total amount of heat in the water

3. If the mass of ice added to the cup increases, the total energy in the cup will decrease or increase1. When the mass of the ice added to the cup increases, the amount of thermal energy needed to change the temperature of the ice decreases or increases

2. When the students measure the temperature of the water in the cups during the investigation, what is it the students are measuring?

Total kinetic energy of the water

Average kinetic energy of the water

Total amount of heat in the water

3. If the mass of ice added to the cup increases, the total energy in the cup will decrease or increase

<h2>please mark me as brainliest. ......</h2>

<h2>my friend. ....please help me .....</h2>
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Answer and Explanation: A charge exerts a force over another charge even if they are very far apart. This force is called <u>Electrostatic</u> <u>Force</u>.

If the two charges have the same sign, e.g. both aare positive, the force between them is opposite. If they have opposite sign, the force is towards each other. In other words, for electrostatic force, equal charges repel and different charges attract.

So,

1. If Q2 and Q3 have opposite signs, it is TRUE force in Q2 will go the left;

2. If the 2 are negative, they have the same sign, so it's FALSE force is to the right;

Sentences 3 and 4 are also TRUE due to the reasons described above;

5. If the charges have opposite signs, it means force is towards each other, or, to the right, so the sentence is TRUE;

1. Force is directly proportional to charges in Coulomb [C] and inversely proportional to distance squared in [m]:

F=\frac{k.q.Q}{r^{2}}

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Calculating force between 1 and 2:

F_{12}=\frac{9.10^{9}(1.9.10^{-6})(2.84.10^{-6})}{(0.301)^{2}}

F_{12}=536.02.10^{-3} N

Force between 2 and 3:

F_{23}=\frac{9.10^{9}(2.84.10^{-6})(3.03.10^{-6})}{(0.169)^{2}}

F_{23}=2711.63.10^{-3} N

Total force is the net force. Since Q2 is negative and the others are positive, force of 2 related to 1 is to left and related to 3 is to the right. Therefore, total force is the difference between those two forces:

F_{T}=2711.63.10^{-3}-536.02.10^{-3}

F_{T}=2175.61.10^{-3} N

The total force on Q2 is 2175.61 x 10⁻³ N

2. For net force to be 0, F_{13}=F_{23}. Suppose distance from 1 to 3 is x, then from 2 to 3 is x-0.301

Calculating:

\frac{k(1.90.10^{-6})(3.03.10^{-6})}{x^{2}}=\frac{k(2.84.10^{-6})(3.03.10^{-6})}{(x-0.301)^{2}}

\frac{5.757.10^{-12}}{x^{2}} =\frac{8.6052.10^{-12}}{x^{2}-0.602x+0.090601}

\frac{5.757.10^{-12}}{8.6052.10^{-12}}=\frac{x^{2}}{x^{2}-0.602x+0.090601}

x^{2}=0.67x^{2}-0.40x+0.061

0.33x^{2}+0.40x-0.061=0

roots = 0.14 or -1.35

Solving quadratic equation gives 2 roots, but one of the roots is negative. As distance is a measure that cannot be negative, the solution is x = 0.14.

The distance of Q3 relative to Q1 is 0.14 m

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