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zimovet [89]
3 years ago
6

Which of the following is least likely to be a scientific experiment?

Physics
1 answer:
nikitadnepr [17]3 years ago
3 0
D should be the answer
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Quick please and will give Brainliest!!!
masha68 [24]

25 nC

That is the answer

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3 years ago
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A liquid of density 1200kg/m³ is filled in a beaker upto the depth of 50 cm. calculate the pressure at bottom of the breaker.(g=
sweet-ann [11.9K]
  • Density=1200kg/m^3=p
  • Height=50cm=0.5m=h
  • Acceleration due to Gravity=9.8m/s^2=g

\boxed{\sf Pressure=pgh}

\\ \qquad\quad\sf{:}\dashrightarrow Pressure=1200(0.5)(9.8)

\\ \qquad\quad\sf{:}\dashrightarrow Pressure=600(9.8)

\\ \qquad\quad\sf{:}\dashrightarrow Pressure=5880Pa

6 0
3 years ago
A 2.5-kg ball and a 5.0-kg ball have an elastic collision. Before the collision, the 2.5-kg ball was at rest and the other ball
lesantik [10]

The kinetic energy of 2.5 kg ball after collision is 27.09 J.

Answer:

Explanation:

In elastic collision, the sum of momentum of the objects before collision will be equal to the sum of momentum of the objects after collision.  

We know that momentum is the product of mass and velocity acting on any object.

So, the conservation of energy in elastic collision leads to following equation:

M_{1} u_{1} +M_{2} u_{2}=M_{1}  v_{1}+M_{2}  v_{2}

Since, the momentum is conserved ,the kinetic energy will also be conserved in elastic collision. So

M_{1} u_{1} ^{2}+M_{2} u_{2} ^{2}=M_{1}v_{1} ^{2}+  M_{2}v_{2} ^{2}

Since initial velocity for M1 ball is zero, then

M_{2} u_{2}=M_{1}  v_{1}+M_{2}  v_{2}

and

M_{2} u_{2} ^{2}=M_{1}v_{1} ^{2}+  M_{2}v_{2} ^{2}

So, on solving all the above equation, we get an equation for velocity and that is

\frac{2M_{2}u_{2} }{(M_{1}+M_{2}  }=final velocity of ball with mass 2.5 kg

v = \frac{2(5*3.5)}{2.5+5}=4.67 m/s

So kinetic energy will be 1/2 mv2

Kinetic energy of 2.5 kg ball is \frac{1}{2}*2.5*(4.67)^{2}  =27.09 J

So the kinetic energy of 2.5 kg ball after collision is 27.09 J.

6 0
3 years ago
How would you determine how much error there is between a vector addition and the real results
chubhunter [2.5K]
Desired operation: A + B = C; {A,B,C) are vector quantities. 

<span>Issue: {A,B} contain error (measurement or otherwise) </span>

<span>Objective: estimate the error in the vector sum. </span>

<span>Let A = u + du; where u is the nominal value of A and du is the error in A </span>
<span>Let B = v + dv; where v is the nominal value of B and dv is the error in B </span>
<span>Let C = w + dw; where w is the nominal value of C and dw is the error in C [the objective] </span>

<span>C = A + B </span>

<span>w + dw = (u + du) + (v + dv) </span>

<span>w + dw = (u + v) + (du + dv) </span>

<span>w = u+v; dw = du + dv </span>

<span>The error associated with w is the vector sum of the errors associated with the measured quantities (u,v)</span>
6 0
3 years ago
A echo occurs when sound does what?
klio [65]
Echoes occur when a reflected soundwave reaches the ear more than 0.1 seconds after the original sound wave was heard. ... There will be an echoinstead of a reverberation. Reflection of sound waves off of surfaces is also affected by the shape of the surface.

(mark as brainly please)
8 0
3 years ago
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