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3 years ago

Ben is 3 times as old as Daniel and is also 4 years older than Daniel. How old is Daniel?

1 answer:

5 0

B=3d and b=d+4

Since b=b we can say:

3d=d+4 subtract d from both sides

2d=4 divide both sides by 2

d=2

Daniel is 2 years old. (and Ben is 6 years old)

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How can solve this ???

poizon [28]

Answer: $11,808

<u>Step-by-step explanation:</u>

2011 - 1995 = 16

418t + 5120

= 418(16) + 5120

= 6688 + 5120

= 11,808

5 0

3 years ago

6k^3+10k^2−56k and 5(7k−3)(3k−7)share a common binomial factor. What binomial factor do they share?

goldenfox [79]

Answer:

Step-by-step explanation:

$6k^3+10k^2-56k\\2k(3k^2+5k-28)\\=2k[3k^2+12k-7k-28]\\=2k[3k(k+4)-7(k+4)]\\=2k(k+4)(3k-7)$

common factor is 3k-7

8 0

2 years ago

Question 25 the sum of three numbers is 79 . the second number is 9 less than the first. the third number is 2 times the first.

g100num [7]

I believe the numbers are 22, 13, and 44.

4 0

3 years ago

One of our brainliest, Konrad509, made this:

Reil [10]

$\dfrac{B_x \sqrt{74_x}}{1D_x}+J_x51_x=4G3_x$

A=10, B=11, C=12, etc.

$\dfrac{11\cdot x^0\cdot \sqrt{7\cdot x^1+4\cdot x^0}}{1\cdot x^1+13\cdot x^0}+19\cdot x^0\cdot (5\cdot x^1+1\cdot x^0)=4\cdot x^2+16\cdot x^1+3\cdot x^0\\\\\dfrac{11\sqrt{7x+4}}{x+13}+19(5x+1)=4x^2+16x+3\\\\\dfrac{11\sqrt{7x+4}}{x+13}+95x+19=4x^2+16x+3\\\\11\sqrt{7x+4}+95x(x+13)+19(x+13)=(4x^2+16x+3)(x+13)\\\\11\sqrt{7x+4}+95x^2+1235x+19x+247=4x^3+52x^2+16x^2+208x+3x+39\\\\11\sqrt{7x+4}=4x^3-27x^2-1043x-208\\\\121(7x+4)=(4x^3-27x^2-1043x-208)^2$

$121(7x+4)=(4x^3-27x^2-1043x-208)^2\\\\847x+484=16 x^6 - 216 x^5 - 7615 x^4 + 54658 x^3 + 1099081 x^2 + 433888 x + 43264\\\\16 x^6 - 216 x^5 - 7615 x^4 + 54658 x^3 + 1099081 x^2 + 433041 x +42780=0$

Now, the "only" thing that remains to do is solving the above equation.

While making this problem I only made sure it has a solution. I didn't try to solve it myself and I didn't know it will end up with such "convoluted" polynomial. Sorry to everyone who tried to solve it... m(_ _)m

I think the best way to approach it is using the rational root theorem since we know that $x\in\mathbb{N}$ . Moreover we can deduce that $x\geq19$ since there is $J$ and $J=19$ .

After you succesfully solve it, you should get the answer $x=20$ .

7 0

3 years ago

Solve the following system of equations by linear combination: 3d – e = 7 d + e = 5

SashulF [63]

3d - e = 7d + e = 5 ⇒ 3d - e = 5
7d + e = 5

3d - e = 5
7d + e = 5 +
-----------------------
10d / = 10
10d = 10
d = 10/10
d = 1

7d + e = 5
7×1 + e = 5
7 + e = 5
e = 5 - 7
e = -2

8 0

3 years ago