Answer:
The numerator must be greater than 16
Step-by-step explanation:
We are told that a certain fraction is greater than 2. Thus, if the numerator and denominator are x and y respectively, then we have;
x/y > 2
We are further told that the denominator is 8.
Thus;
x/8 > 2
Multiply both sides by 8 to give;
x > 16
Thus,the numerator must be greater than 16.
Answer:
7ft 8in is left over
Step-by-step explanation:
Let x be the 1st odd number, and x+2 the second odd consecutive number:
(x)(x + 2) = 6[((x) + (x+2)] -1
x² + 2x = 6(2x + 2) - 1
x² + 2x = 12x +12 - 1
And x² - 10x - 11=0
Solve this quadratic expression:
x' = [+10 +√(10²- 4.(1)(-11)]/2 and x" = [+10 -√(10²- 4.(1)(-11)]/2
x' = [10 + √144]/2 and x" = [10 - √64]/2
x' = (10+12)/2 and x" = (10-12)/2
x = 11 and x = -1
We have 2 solutions that satisfy the problem:
1st for x = 11, the numbers at 11 and 13
2nd for x = - 1 , the numbers are -1 and +1
If you plug each one in the original equation :(x)(x + 2) = 6[((x) + (x+2)] -1
you will find that both generates an equlity
Answer:
8 : 28
x2 x2
16:56
Step-by-step explanation:
Don't be shy about using actual parentheses and commas.
Line through (1,8) perpendicular to
The perpendicular family is gotten by swapping the coefficients on x and y, negating exactly one of them. The constant is given directly by the point we're through:
Let's clear the fractions by multiplying both sides by 20.
Might as well stop here.
Answer: 25 x + 16 y = 153
