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Blababa [14]
3 years ago
10

Ben is 3 times as old as Daniel and is also 4 years older than Daniel. How old is Daniel?

Mathematics
1 answer:
Georgia [21]3 years ago
5 0
B=3d and b=d+4 

Since b=b we can say:

3d=d+4  subtract d from both sides

2d=4  divide both sides by 2

d=2

Daniel is 2 years old.  (and Ben is 6 years old)
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-8x+32=4(-2-4x)<br>What does X equal ​
marshall27 [118]

Answer:

x = - 5

Step-by-step explanation:

Given

- 8x + 32 = 4(- 2 - 4x) ← distribute parenthesis on right side

- 8x + 32 = - 8 - 16x ( add 16x to both sides )

8x + 32 = - 8 ( subtract 32 from both sides )

8x = - 40 ( divide both sides by 8 )

x = - 5

7 0
3 years ago
Solve for t -18 = 6t
mihalych1998 [28]

-18 = 6t

Divide both sides by 6

-18/6 =6t/6

-3 = t

t= -3

5 0
1 year ago
Please help final exam
Finger [1]
I think the answer here would be D. When it rains several inches, the water level of the lake increases, because the word Causation means: the relationship between cause and effect; causality. If it rains a lot, it will cause the lake to increase. ( if help on ur exam use Socratic and brainly!❤️) Hope you do well!!!
6 0
3 years ago
Given 2 events a and b, and that p(a)=0.30, p(b)=0.45, p(a u b)=0.60. find the probability p(a∩b).
pickupchik [31]
P(a U b) = p(a) + p(b) - p(a ∩ b)

<=>

p(a ∩ b) = p(a) + p(b) - p(a U b)

I let you do the maths :)
3 0
4 years ago
A coin will be tossed three times, and each toss will be recorded as heads (H) or tails (T). Give the sample space describing al
cricket20 [7]

Answer:

Sample space:

{HHH, HHT, HTH, HTT, THH, THT, TTH, TTT}

Third toss is heads:

{HHT, HTT, THT, TTT}

First toss is heads, second tails and third heads:

{HTH}

Explanation:

In order to find the sample space we need to write all the possible outcomes from tossing the coin three times.You can start by writting all the possible outcomes for the first toss being a head and finish with all the possible outcomes for the first toss being Tails. The number of elements in the sample space can be found by multiplying the possible outcomes of each toss together, so 2*2*2=8

{HHH, HHT, HTH, HTT, THH, THT, TTH, TTT}

For the third toss being heads we will have one restriction this time. Which is that the third toss is Tails. You can take the elements from the sample space where the third element is a tails. In this case, the number of elements can be calculated by multiplying the possible outcomes for only the first two tosses 2*2=4

{HHH, HHT, HTH, HTT, THH, THT, TTH, TTT}

For first toss is heads, second tails and third heads there is only one possible way for you to get this outcome so there is only one element to this set.

{HTH}

4 0
3 years ago
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