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marissa [1.9K]
3 years ago
7

X=-42 what slope if a line is perpendicular to it and what slope of the line is parallel

Mathematics
1 answer:
alexgriva [62]3 years ago
8 0

Answer:

Parallel is undefined

Perpendicular is 0

Step-by-step explanation:

The line x = -42 is a vertical line through the x-axis. As such its slope is undefined. All parallel lines have the same slope and will also be undefined. Perpendicular lines will be lines horizontal through the y-axis. This means the slope of any perpendicular line to it will be 0.

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Find the Domain and range of each relation. <br> 1. Q= {(3,4), (-4,1), (2,5), (-4,1), (0,0)}
zimovet [89]

Answer:

Step-by-step explanation:

domain is all ur x values.....

domain = { -4,0,2,3}....u only have to write them once if they repeat

range is all ur y values....

range = { 0,1,4,5}

7 0
3 years ago
Which of these strategies would eliminate a variable in the system of equations? ​8x+8y=2 8x+5y=1 ​ Add the equations. (Choice B
harkovskaia [24]

Answer:

B. Subtract the bottom equation from the top equation.

Step-by-step explanation:

When looking at the two equations:

8x + 8y = 2

8x + 5y = 1

We can easily get rid of the x variable by subtracting the two equations from each other since the terms are equivalent. This would allow us to solve for the y value, which we could plug into the an equation to solve for the x value.

7 0
3 years ago
Read 2 more answers
On the scale drawing of a car, the length from bumper to bumper is 6 inches. The car’s actual length, from bumper to bumper, is
dimulka [17.4K]

Answer:

  • 3/8 in/ft
  • 1/32 . . . (pure number, no units)

Step-by-step explanation:

The ratio can be expressed directly as ...

... (6 in)/(16 ft) = 3/8 in/ft

This can be read or used in different ways:

  • 3/8 in = 1 ft
  • 3 in = 8 ft

Or, the units can be made compatible and the ratio expressed as a pure number.

... (1/2 ft)/(16 ft) = (1/32) ft/ft = 1/32

This means whatever measurement is made on the model, the actual vehicle measurement is 32 times that.

4 0
4 years ago
What is the area of the sector ?​
worty [1.4K]

They forget to say "not to scale".  I'm guessing this is trig because I don't see another way to do it.

Let's consider x=chord PQ first.  By the Law of Cosines

x^2 = 3^2 + 5^2 - 2(3)(5) \cos 81^\circ = 34 - 30\cos 81^\circ

We have an isosceles triangle formed by two radii of 9 cm and x=PQ.  By the Law of Cosines again,

x^2 = 9^2 + 9^2 - 2(9)(9) \cos B

x^2 = 162 - 162 \cos B

\cos B = \dfrac{162 - x^2}{162} = 1 - \dfrac{x^2}{162}

\cos B = 1 - \dfrac{34 - 30\cos 81^\circ}{162}

B = \arccos \left(1 - \dfrac{34 - 30\cos 81^\circ }{162} \right)

The area of the circle is the fraction given by the angle,

A = \dfrac{B}{360^\circ} \pi r ^2

A \approx \dfrac{ \arccos \left(1 - \dfrac{34 - 30\cos 81^\circ}{162} \right) }{360} (3.142)9^2

A\approx 24.7474332960707

Answer: 24.7 sq cm

8 0
3 years ago
Please help me solve this
Tema [17]

Answer:

Step-by-step explanation:

I think it is she sped up and passed susana since it shows it in the graph.

5 0
3 years ago
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