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3 years ago

11

HELP I NEED THIS IN THE NEXT 15 MINUTES!!!!!

1 answer:

Yuliya22 [10]3 years ago

8 0

Answer:

40

Explanation:

40. minuts. because. is. goin. and. back

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True/False: The core, mantle, and crust explanation for the Earth's layers is outdated and now we use the 5 layer explanation. *

nekit [7.7K]

Answer:

False

Explanation:

We still use the old way. It's easier to understand the old way, and its NOT outdated.

3 0

4 years ago

True or False: The average atomic mass is always closer to the isotope with the largest mass

svlad2 [7]

The awnser would be True. Hope I helped!

3 0

3 years ago

Starting from zero, the electric current takes 2 seconds to reach half its maximum possible value in an RL circuit with a resist

Leno4ka [110]

Answer:

time=4s

Explanation:

we know that in a RL circuit with a resistance R, an inductance L and a battery of emf E, the current (i) will vary in following fashion

$i(t)=\frac{E}{R}(1-e^\frac{-t}{\frac{L}{R}})$ , where $i$ max= $\frac{E}{R}$

Given that, at i(2)= $\frac{imax}{2} =\frac{E}{2R}$

⇒ $\frac{E}{2R}=\frac{E}{R}(1-e^\frac{-2}{\frac{L}{R}})$

⇒ $\frac{1}{2}=1-e^\frac{-2}{\frac{L}{R}}$

⇒ $\frac{1}{2}=e^\frac{-2}{\frac{L}{R}}$

Applying logarithm on both sides,

⇒ $log(\frac{1}{2})=\frac{-2}{\frac{L}{R}}$

⇒ $log(2)=\frac{2}{\frac{L}{R}}$

⇒ $\frac{L}{R}=\frac{2}{log2}$

Now substitute $i(t)=\frac{3}{4}imax=\frac{3E}{4R}$

⇒ $\frac{3E}{4R}=\frac{E}{R}(1-e^\frac{-t}{\frac{L}{R}})$

⇒ $\frac{3}{4}=1-e^\frac{-t}{\frac{L}{R}}$

⇒ $\frac{1}{4}=e^\frac{-t}{\frac{L}{R}}$

Applying logarithm on both sides,

⇒ $log(\frac{1}{4})=\frac{-t}{\frac{L}{R}}$

⇒ $log(4)=\frac{t}{\frac{L}{R}}$

⇒ $t=log4\frac{L}{R}$

now subs. $\frac{L}{R}=\frac{2}{log2}$

⇒ $t=log4\frac{2}{log2}$

also $log4=log2^{2}=2log2$

⇒ $t=2log2\frac{2}{log2}$

⇒ $t=4$

5 0

3 years ago

If this resolving power is diffraction-limited, to what effective diameter of your eye's optical system does this correspond? us

ZanzabumX [31]

"This resolving power" was obviously stated earlier, somewhere before the point where you started copying. With no resolving power specified, there's actually no question, and so no answer.

5 0

4 years ago

You have been hired by a "storm chaser" as an assistant. This individual loves to find locations at which tornadoes and violent

Studentka2010 [4]

Answer:

58.44 C

Explanation:

Electric field is found by

$E=\frac {\sigma}{\epsilon_o}=\frac {Q}{A\epsilon_o}$

Therefore, the charge is

$Q=EA\epsilon_o
$

$Q= 4.00 ✕ 10^{6} N/C*1.65 *10^{6} m^{2}*8.854*10^{-12}= 58.4364 C
$

Therefore, required charge is 58.44 C

5 0

3 years ago