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3 years ago

Would it be correct to say the Doppler Effect is the apparent change in the speed of a wave due to the motion of the source?

Physics

2 answers:

tatiyna3 years ago

6 0

Yes that would be correct. But if its an essay I'd be a bit more elaborate and give examples.

Alex3 years ago

6 0

The answer for this would be frequency i just did it

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The moon is 3x10^5 km away from Nepal and the mass of the moon is 7x10^22 kg. Calculate the force with which the Moon pulls ever

hammer [34]

Answer:

Approximately $5.19 \times 10^{-5}\; \rm N$ .

Explanation:

Let $G$ denote the gravitational constant. ( $G \approx 6.67 \times 10^{-11} \; \rm N \cdot kg^{-2} \cdot m^{2}$ .)

Let $M$ and $m$ denote the mass of two objects separated by $r$ .

By Newton's Law of Universal Gravitation, the gravitational attraction between these two objects would measure:

$\displaystyle F = \frac{G \cdot M \cdot m}{r^{2}}$ .

In this question: $M = 7 \times 10^{22}\; \rm kg$ is the mass of the moon, while $m = 1\; \rm kg$ is the mass of the water. The two are $r = 3\times 10^{5}\; \rm km$ apart from one another.

Important: convert the unit of $r$ to standard units (meters, not kilometers) to reflect the unit of the gravitational constant $G$ .

$\displaystyle r = 3 \times 10^{5}\; \rm km \times \frac{10^{3}\; \rm m}{1\; \rm km} = 3 \times 10^{8}\; \rm m$ .

$\begin{aligned} F &= \frac{G \cdot M \cdot m}{r^{2}} \\ &= \frac{6.67 \times 10^{-11}\; \rm N \cdot kg^{-2}\cdot m^{2} \times 7 \times 10^{22}\; \rm kg \times 1\; \rm kg}{(3 \times 10^{8}\; \rm m)^{2}} \\ &\approx 5.19 \times 10^{-5} \; \rm N\end{aligned}$ .

5 0

3 years ago

200 J of work is done when a force is applied to an object and the object moves 10 m to the right. How much Force was applied?

ArbitrLikvidat [17]

Answer:

20N

Explanation:

Given parameters:

Work done = 200J

Distance moved = 10m

Unknown:

Amount of force applied =?

Solution:

Work done is the force applied on a body to move it in the direction of the force.

Work done = force x distance

The unit of work done is in joules

Since the unknown is force, we make it the subject of the expression;

Force = $\frac{Work done}{distance}$

Force = $\frac{200}{10}$ = 20N

5 0

4 years ago

Help asapppppppppppppppppp

Lana71 [14]

Answer:

I’m pretty sure the answer is distance

Explanation:

Hope this helps! Sorry if it’s wrong.

5 0

3 years ago

A small first-aid kit is dropped by a rock climber who is descending steadily at 1.3 m/s. After 2.5 s, what is the velocity of t

Artyom0805 [142]

Answer:

D = 30.625 m

Explanation:

given,

Speed of the climber = 1.3 m/s

time = 2.5 s

acceleration due to gravity = 9.8 m/s²

initial speed of the kit = 1.3 m/s

velocity of the kit after 2.5 s

using equation of motion

v = u + a t

v = 1.3 + 9.8 x 2.5

v = 25.8 m/s

distance travel by the kit in 2.5 s

v² = u² + 2 g h

25.8² = 1.3² + 2 x 9.8 x h

19.6 h = 663.95

h = 33.875 m

distance travel by the rock climber in 2.5 s

distance = speed of climber x time

h' = 1.3 x 2.5

h' = 3.25 m

Distance between kit and rock climber

D = h - h'

D = 33.875 - 3.25

D = 30.625 m

The kit is 30.625 m below climber.

8 0

3 years ago

I need help with this problem please asap

Contact [7]

Their different just put because their different

8 0

3 years ago

Read 2 more answers