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2 years ago

I = 30A and R = 30; what is V? A. 900v B.90v C.10v D.0.1v

Physics

1 answer:

Marat540 [252]2 years ago

8 0

Answer:

$V = 900\; {\rm V}$ for a resistor where $I = 30\; {\rm A}$ and $R = 30\; {\rm \Omega}$ .

Explanation:

By Ohm's Law, if the electric resistance of a resistor is $R$ and the current going through that resistor is $I$ , the voltage across that resistor would be $V = I\, R$ .

Note that electric resistance is typically measured in Ohms, where $1\; {\rm \Omega} = 1\; {\rm V \cdot A^{-1}}$ .

Given that $I = 30\; {\rm A}$ and $R = 30\; {\rm \Omega}$ for the resistor in this question, apply the formula $V = I\, R$ to find the voltage $V$ across this resistor:

$\begin{aligned} V &= I\, R \\ &= 30\; {\rm A} \times 30\; {\rm \Omega} \\ &= 30\; {\rm A} \times 30\; {\rm V \cdot A^{-1}} \\ &= 900\; {\rm V} \end{aligned}$ .

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sukhopar [10]

Explanation:

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2 years ago

A football wide receiver rushes 16 m straight down the playing field in 2.9 s (in the positive direction). He is then hit and pu

vredina [299]

Answer:

a) $v_1=5.5172\ m.s^{-1}$

b) $v_2=-1.5152\ m.s^{-1}$

c) $v_3=4.6154\ m.s^{-1}$

d) $v_{avg}=3.8462\ m.s^{-1}$

Explanation:

Given:

distance down the field in the first interval, $d_1=16\ m$

time duration of the first interval, $t_1=2.9\ s$

distance down the field in the second interval, $d_2=-2.5\ m$

time duration of the second interval, $t_2=1.65\ s$

distance down the field in the third interval, $d_3=24\ m$

time duration of the third interval, $t_3=5.2\ s$

velocity in the first interval:

$v_1=\frac{d_1}{t_1}$

$v_1=\frac{16}{2.9}$

$v_1=5.5172\ m.s^{-1}$

velocity in the second interval:

$v_2=\frac{d_2}{t_2}$

$v_2=\frac{-2.5}{1.65}$

$v_2=-1.5152\ m.s^{-1}$

velocity in the third interval:

$v_3=\frac{d_3}{t_3}$

$v_3=\frac{24}{5.2}$

$v_3=4.6154\ m.s^{-1}$

We know that the average velocity is given as the total displacement per unit time.

$v_{avg}=\frac{d_1+d_2+d_3}{t_1+t_2+t_3}$

$v_{avg}=\frac{16-2.5+24}{2.9+1.65+5.2}$

$v_{avg}=3.8462\ m.s^{-1}$

3 0

3 years ago

A neon lamp produces what kind of visible spectrum?

Shalnov [3]

Answer:

Discrete

Explanation:

There can be many kind of visible spectrum. Some of them are as follows :Infrared, Continuous , Blackbody and Discrete.

A neon lamp produces discrete kind of visible spectrum. In this type of spectrum, the spectrum consists of different colors. It means that the neon lamp is made up of different colors or individual frequencies.

Hence, a neon lamp produces discrete visible spectrum.

5 0

3 years ago

A net force of 2070N acts on a car with a mass of 1350 kg. What is the acceleration of the car?

emmasim [6.3K]

Answer:

Below

Explanation:

To find the acceleration of the car, we can use this formula :

acceleration = net force / mass

acceleration = 2070 N / 1350 kg

acceleration = 1.53333 m/s^2

acceleration = 1.53 m/s^2

Hope this helps!

8 0

2 years ago

A puddle of water has a thin film of gasoline floating on it. A beam of light is shining perpendicular on the film. If the wavel

g100num [7]

Answer:

option A

Explanation:

Given,

wavelength of light, $\lambda = 560\ nm$

refractive index of gasoline, n₁ = 1.40

Refractive index of water, n₂ = 1.33

thickness of the film, t = ?

Condition of constructive interference is given by

$2 n t = (m+\dfrac{1}{2})\lambda$

For minimum thickness of the film m = 0

From the question we can clearly observe that phase change from gasoline to air

so, n = 1.4

$2 \times 1.4 \times t = \dfrac{560}{2}$

$t = 100\ nm$

Hence, the correct answer is option A

7 0

4 years ago