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Llana [10]
3 years ago
5

Substance X transfers thermal energy to substance Y through conduction. What is an accurate conclusion about the condition of bo

th substances before conduction occurred?
Physics
2 answers:
bagirrra123 [75]3 years ago
7 0
In order for the heat to be transferred from the body X to the body Y via conduction, there must be a difference in temperature of body X with respect to body Y. Body X must have a higher temperature than body Y. This process continues until both bodies arrive at thermal equilibrium, meaning they both have the same temperature. 
Olin [163]3 years ago
3 0

Answer:

Substance X’s molecules were faster than substance Y’s.

Explanation:

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Two blocks of the same mass but made of different material slide across a horizontal, rough surface and eventually come to rest.
Akimi4 [234]

Answer:

a. \mathbf{F_{f_2} = 2 F_{f1}}, \mathbf { since \ the \ force \ o f \ friction  \ is \ represented  \ as  \ the \  slope \ for \ each  \ of  \ the \ two  \ curves.}

Explanation:

From the information given;

Using the work-energy theorem

ΔKE = W = \mathbf{ F_f \times r}

K = \mathbf{ F_f \times r}

∴

\dfrac{K_1}{K_2} = \dfrac{F_{f1}}{F_{f2}} (\dfrac{r_1}{r_2})

Since K_1 = K_2 and r_1 = 4, and r_2 = 2 (from the missing diagram which is attached below)

Then;

1 = \dfrac{F_{f1}}{F_{f2}} (\dfrac{4 \ m}{2 \ m})

\mathbf{F_{f_2} = 2 F_{f1}}

5 0
3 years ago
An object's buoyant force and weight mean the same thing.<br><br>A. True<br><br>B. False​
german

Answer:

False

Explanation:

No. The buoyant force on an object is the portion of its weight that appears to vanish

when the object is in any fluid (could be either a liquid or a gas).

If the object happens to float in a particular fluid, then the buoyant force at that moment

is equal to the object's weight.

Notice that the buoyant force on an object will be different in different fluids.

6 0
3 years ago
Express in words AND mathematically the relationship between…<br> Period and frequency
castortr0y [4]
Frequency = how many waves you get per sec
Period = how long each wave takes

Period = 1/frequency
6 0
3 years ago
A car traveling at 23 m/s starts to decelerate steadily. It comes to a complete stop in 5 seconds. What is its acceleration?
kykrilka [37]
We could determine the acceleration using this formula
\boxed{a= \dfrac{v_{1}-v_{0}}{t} }

Given from the question v₀ = 23 m/s, v₁ = 0 (the car stops), t = 5 s
plug in the numbers
a= \dfrac{v_{1}-v_{0}}{t}
a= \dfrac{0-23}{5}
a= \dfrac{-23}{5}
a = -4.6
The acceleration is -4.6 m/s²
8 0
3 years ago
Does anyone know how to solve this??
Scrat [10]

I uploaded the answer to a file hosting. Here's link:

tinyurl.com/wtjfavyw

7 0
2 years ago
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