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3 years ago

9

What does 0.03703703703 equal in fractions

2 answers:

Zinaida [17]3 years ago

6 0

Step 1: Write down the decimal<span> divided by 1, like this: </span>decimal<span> 1. Step 2: Multiply both top and bottom by 10 for every number after the </span>decimal<span> point. (For example, if there are two numbers after the </span>decimal<span> point, then use 100, if there are three then use 1000, etc.) Step 3: Simplify (or reduce) the </span>fraction<span>.</span>

egoroff_w [7]3 years ago

3 0

The fraction form of <span>0.03703703703 is 1/27</span>

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Find the general solution of (x+3)y’=2y

gregori [183]

Answer:

$y=C(x+3)^2$

Step-by-step explanation:

We are given:

$\displaystyle (x+3)y^\prime=2y$

Separation of Variables:

$\displaystyle \frac{1}{y}\frac{dy}{dx}=\frac{2}{x+3}$

So:

$\displaystyle \frac{dy}{y}=\frac{2}{x+3} \, dx$

Integrate:

$\displaystyle \int\frac{dy}{y}=\int\frac{2}{x+3}\, dx$

Integrate:

$\displaystyle \ln|y|=2\ln|x+3|+C$

Raise both sides to e:

$|y|=e^{2\ln|x+3|+C}$

Simplify:

$|y|=(e^{\ln|x+3|})^2\cdot e^C$

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5 0

2 years ago

Plz help with this I don’t really get it

Greeley [361]

Answer:

D

Step-by-step explanation:

Associative Property of Multiplication is a(bc) = (ab)c

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6 0

2 years ago

Which point is located at (2, 3)?<br><br><br><br><br> A<br> B<br> C<br> Or<br> D

marin [14]

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Step-by-step explanation:

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2 years ago

Simon has more money than Kande. if Simon gave Kande K20, they would have the same amount. While if Kande gave Simon $22, Simon

motikmotik

Given parameters;

Let us solve this problem step by step;

Let us represent Simon's money by S

Kande's money by K

Simon has more money than Kande

S > K

if Simon gave Kande K20, they would have the same amount;

if Simon gives $20, his money will be S - 20 lesser;

When Kande receives $20, his money will increase to K + 20

S - 20 = K + 20 ------ (i)

While if Kande gave Simon $22, Simon would then have twice as much as Kande;

if Kande gave Simon $22, his money will be K - 22

Simon's money, S + 22;

S + 22 = 2(K - 22) ------ (ii)

Now we have set up two equations, let us solve;

S - 20 = K + 20 ---- i

S + 22 = 2(K - 22) ; S + 22 = 2K - 44 ---- ii

So, S - 20 = K + 20

S + 22 = 2K - 44

subtract both equations;

-20 - 22 = (k -2k) + 64

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k = 106

Using equation i, let us find S;

S - 20 = K + 20

S - 20 = 106 + 20

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