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mars1129 [50]
3 years ago
11

1. Define and give a visual example of the Commutative Property.

Mathematics
1 answer:
strojnjashka [21]3 years ago
7 0
Start with wants in the ( ) and add so c+3 = 3c x 7 = 27c + -4 then you go to (3c - 2) so your answer is 30c - 6 i think
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Find the additive inverse of -7 - 5
PolarNik [594]

Answer:

this is your answer.

Please mark me as brainliest.thanks!!

5 0
3 years ago
Hi! can you please help me and show me how you got your answer? thank you!
Kamila [148]

Answer:

Step-by-step explanation:multipy -4x and 4 by 2 were the 8x and the -8x would cancel then add and bring down answer of x=15

5 0
3 years ago
The answer and how you got it
mart [117]
The answer is 12
12-(5+3)=4
4+8=12
8 0
4 years ago
A sample of size 200 will be taken at random from an infinite population. given that the population proportion is 0.60, the prob
Musya8 [376]

Let p be the population proportion. <span>
We have p=0.60, n=200 and we are asked to find P(^p<0.58). </span>
The thumb of the rule is since n*p = 200*0.60 and n*(1-p)= 200*(1-0.60) = 80 are both at least greater than 5, then n is considered to be large and hence the sampling distribution of sample proportion-^p will follow the z standard normal distribution. Hence this sampling distribution will have the mean of all sample proportions- U^p = p = 0.60 and the standard deviation of all sample proportions- δ^p = √[p*(1-p)/n] = √[0.60*(1-0.60)/200] = √0.0012. 
So, the probability that the sample proportion is less than 0.58 
= P(^p<0.58) 
= P{[(^p-U^p)/√[p*(1-p)/n]<[(0.58-0.60)/√0... 
= P(z<-0.58) 
= P(z<0) - P(-0.58<z<0) 
= 0.5 - 0.2190 
= 0.281 
<span>So, there is 0.281 or 28.1% probability that the sample proportion is less than 0.58. </span>

4 0
4 years ago
I NEED HELP PLSSSSSSSS
AVprozaik [17]

Answer:

X >>>>> Y

–1 >>>> 16

0 >>>>> 8

1 >>>>> 4

2 >>>>> 2

3 >>>>> 1

Step-by-step explanation:

From the question given above,

y = 8 × (½)ˣ

When x = –1, y =?

y = 8 × (½)ˣ

y = 8 × (½)¯¹

y = 8 × 2

y = 16

When x = 1, y =?

y = 8 × (½)ˣ

y = 8 × (½)¹

y = 8 × ½

y = 4

When x = 2, y =?

y = 8 × (½)ˣ

y = 8 × (½)²

y = 8 × ¼

y = 2

When x = 3, y =?

y = 8 × (½)ˣ

y = 8 × (½)³

y = 8 × ⅛

y = 1

SUMMARY:

X >>>>> Y

–1 >>>> 16

0 >>>>> 8

1 >>>>> 4

2 >>>>> 2

3 >>>>> 1

4 0
3 years ago
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