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Lyrx [107]
3 years ago
9

The smell of fresh cut pine is due in part to the cyclic alkene called pinene. Given the following data of pinene: Vapor pressur

e (torr) Temperature (K) 760 429 515 415 Calculate the heat of vaporization, ΔHvap, of pinene.
Chemistry
1 answer:
Sveta_85 [38]3 years ago
4 0

Answer: Heat of vaporization is 41094 Joules

Explanation:

The vapor pressure is determined by Clausius Clapeyron equation:

ln(\frac{P_2}{P_1})=\frac{\Delta H_{vap}}{R}(\frac{1}{T_1}-\frac{1}{T_2})

where,

P_1= initial pressure at  429 K = 760 torr

P_2 = final pressure at 415 K  = 515 torr

= enthalpy of vaporisation = ?

R = gas constant = 8.314 J/mole.K

T_1= initial temperature =  429 K

T_2 = final temperature = 515 K

Now put all the given values in this formula, we get

\log (\frac{515}{760}=\frac{\Delta H}{2.303\times 8.314J/mole.K}[\frac{1}{429K}-\frac{1}{415K}]

\Delta H=41094J

Thus the heat of vaporization is 41094 Joules

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What is the ph of a solution labeled .30 trimethylamine k for trimethylamine is 7.42 x 10^4
valentina_108 [34]

Answer:the pH is 12

Explanation:

First We need to understand the structure of trimethylamine

Due to the grades of the bond in the nitrogen with a hybridization sp3 is 108° approximately, then is generated a dipole magnetic at the upper side of the nitrogen, this dipole magnetic going to attract a hydrogen molecule of the water making the water more alkaline

C3H9N+ H2O --> C3H9NH + OH-

k=\frac{[C3H9NH]*[OH-]}{[C3H9N]}

Then:

The concentration of the trimethylamine is 0.3 and the concentration of the ion C3H9NH is equal to the OH- relying on the stoichiometric equation. We could find the concentration of the OH- ion with the square root of the multiplication between k and the concentration of trimethylamine

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3 years ago
580 grams of boiling water (temperature 100°C, specific heat capacity 4.2 J/K/gram) are poured into an aluminum pan whose mass i
fenix001 [56]

Answer:

81.04°C

Explanation:

Heat loss by water = Heat gained by Aluminum

Heat loss by water;

H = MCΔT

ΔT = 100 -  T2

M = 580g

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H = 580 * 4.2 (100 - T2)

H =  243600  - 2436T2

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H = MCΔT

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c = 0.9

H = 900 * 0.9 (T2 - 24)

H = 810 T2 - 19440

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243600 + 19440 =  810 T2 + 2436T2

263040 = 3246 T2

T2 = 81.04°C

Assumption;

Assume that energy diffuses throughout the pan and water so that all parts reach the same final temperature.

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