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Oksanka [162]
3 years ago
7

Newton contributed to astronomy by:

Chemistry
2 answers:
SCORPION-xisa [38]3 years ago
6 0

Answer:  D

Explanation:

This is the answer because everyone knows he discovered gravity and he conducted scientific experiments to prove them which he also used math for

Hope this helps

stiv31 [10]3 years ago
6 0

Answer:

Newton contributed to astronomy by <u><em>developing theories of gravity and motion.</em></u>

Explanation:

Newton reflected on the fact that bodies weighed on Earth and that the stars revolved around other stars. He imagined that there was a universal force that caused bodies to attract each other. Newton called it "Universal Gravitation Force" or "Gravity."

Then, the force of gravity is the physical force exerted by the mass of a planet on the objects that are within its gravitational field. In other words, this law establishes that bodies, by simply having mass, experience a force of attraction to other bodies with mass.

Objects are attracted according to their mass and the distance between their centers: if the distance increases, the force decreases, and if the mass increases, the Universal Gravitation Force is more intense:

F=G*\frac{M*m}{r^{2} }

where G is the universal gravitation constant, whose value is

This expression indicates that the gravitational force that a point mass M exerts on another point mass m that is at a distance r from the previous one is directly proportional to the product of the masses and inversely proportional to the square of the distances that separates them.

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LiOH+HCL LiCL+H2O represents a double replacement reaction.
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If an object has a mass of 250 grams and a volume of 5 milliliters, what is the density of the object?
ycow [4]

Answer:

<h2>50 g/mL</h2>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume} \\

From the question we have

density =  \frac{250}{5}  \\

We have the final answer as

<h3>50 g/mL</h3>

Hope this helps you

4 0
3 years ago
How many protons and neutrons are there in an atom of 3.K?
pickupchik [31]

Answer:

A: 11 protons and 21 neutrons

Explanation:

Hopefully this helps!

3 0
3 years ago
Which particle diagram represents a mixture of three substances
Anni [7]

Following the key in the diagram (see the attached image), the only particle diagram that represents a mixture of three substances is diagram 2.

To simplify it, let us replace the key in the diagram as follows;

  1. atom of one element = A
  2. atom of different element = B

Diagram 1 consists of only AA and AB

Diagram 2 consists of AA, BB, and AB.

Diagram 3 consists of AA and ABA

Diagram 4 consists of AA and BAB

Thus, only diagram 2 has a mixture of 3 substances.

More on mixtures can be found here: brainly.com/question/6594631

4 0
3 years ago
Determine the rate law, including the values of the orders and rate law constant, for the following reaction using the experimen
olga55 [171]

Answer: Rate law=k[A]^1[B]^2, order with respect to A is 1, order with respect to B is 2 and total order is 3. Rate law constant is 3L^2mol^{-2}s^{-1}

Explanation: Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

Rate=k[A]^x[B]^y

k= rate constant

x = order with respect to A

y = order with respect to A

n = x+y = Total order

a) From trial 1: 1.2\times 10^{-2}=k[0.10]^x[0.20]^y    (1)

From trial 2: 4.8\times 10^{-2}=k[0.10]^x[0.40]^y    (2)

Dividing 2 by 1 :\frac{4.8\times 10^{-2}}{1.2\times 10^{-2}}=\frac{k[0.10]^x[0.40]^y}{k[0.10]^x[0.20]^y}

4=2^y,2^2=2^y therefore y=2.

b) From trial 2: 4.8\times 10^{-2}=k[0.10]^x[0.40]^y    (3)

From trial 3: 9.6\times 10^{-2}=k[0.20]^x[0.40]^y   (4)

Dividing 4 by 3:\frac{9.6\times 10^{-2}}{4.8\times 10^{-2}}=\frac{k[0.20]^x[0.40]^y}{k[0.10]^x[0.40]^y}

2=2^x,2=2^1, x=1

Thus rate law is Rate=k[A]^1[B]^2

Thus order with respect to A is 1 , order with respect to B is 2 and total order is 1+2=3.

c) For calculating k:

Using trial 1:  1.2\times 10^{-2}=k[0.10]^1[0.20]^2

k=3 L^2mol^{-2}s^{-1}.



6 0
3 years ago
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